Answer:
y = one-half x + three-fourths
Step-by-step explanation:
The 2-point form of the equation of a line can be used for starters.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
y = (11/12 -19/20)/(1/3 -2/5)(x -2/5) +19/20 . . . . fill in given values
y = ((55 -57)/60)/((5 -6)/15)(x -8/20) +19/20 . . simplify a little
y = (-1/30)/(-2/30)(x -8/20) +19/20 . . . . . . . . . . and a little more ...
y = 1/2x -4/20 +19/20
y = 1/2x +15/20
y = 1/2x +3/4 . . . . line in slope-intercept form
This isnt something I can do... But draw and label a tape diagram that goes from 0 to 30.
-12/6+2
=-12/6+2/1
=-2/1+2/1
=-2+2/1
=0
From looking at that equation you put this is my solution.
Answer:
- 2(L +W) ≤ 600
- W ≤ 200
- L ≥ 2W
Step-by-step explanation:
We assume the problem wording means the length is to be at least 2 times <em>as long as</em> the width. (<em>Longer than</em> usually refers to a difference, not a scale factor.)
If we let "W" and "L" represent the width and length, respectively, then we can translate the problem statement to ...
2(L + W) ≤ 600 . . . . . . the perimeter is twice the sum of length and width
W ≤ 200 . . . . . . . . . . . . the width is at most 200 inches
L ≥ 2W . . . . . . . . . . . . . the length is at least twice the width
