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kirill115 [55]
2 years ago
11

Find the perimeter of a rectangle if the length is 6y + 10 and the width is y - 3

Mathematics
1 answer:
kipiarov [429]2 years ago
6 0

Step-by-step explanation:

Given that,

  • Length = 6y + 10
  • Width = y – 3

\implies \sf Perimeter = 2(L + W) \\ \implies \sf P= 2(6y + 10 + y - 3) \: units \\  \implies \sf P= 2(7y +7) \: units \\  \implies  \red{\sf P= 14y + 14 \: units} \\

Therefore, perimeter is (14y + 14) units.

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I hope I helped!

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