Find the perimeter of a rectangle if the length is 6y + 10 and the width is y - 3

Mathematics

1 answer:

kipiarov [429]2 years ago

6 0

Step-by-step explanation:

Given that,

Length = 6y + 10
Width = y – 3

$\implies \sf Perimeter = 2(L + W) \\ \implies \sf P= 2(6y + 10 + y - 3) \: units \\ \implies \sf P= 2(7y +7) \: units \\ \implies \red{\sf P= 14y + 14 \: units} \\$

Therefore, perimeter is (14y + 14) units.

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Answer:

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2 years ago

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victus00 [196]

Answer:

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