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kirill115 [55]
3 years ago
11

Find the perimeter of a rectangle if the length is 6y + 10 and the width is y - 3

Mathematics
1 answer:
kipiarov [429]3 years ago
6 0

Step-by-step explanation:

Given that,

  • Length = 6y + 10
  • Width = y – 3

\implies \sf Perimeter = 2(L + W) \\ \implies \sf P= 2(6y + 10 + y - 3) \: units \\  \implies \sf P= 2(7y +7) \: units \\  \implies  \red{\sf P= 14y + 14 \: units} \\

Therefore, perimeter is (14y + 14) units.

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Step-by-step explanation:

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3 years ago
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Rudiy27

Answer:

3x^3-2x^2-4x+1+7/x-2

Step-by-step explanation:

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3 years ago
In triangle PQR, measurement P = 7x+8 , measurement Q = 8x-10, and measurement R = 7x+6 . List the sides in order from shortest
astra-53 [7]

Answer:

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Step-by-step explanation:

Let x be any positive integer, say x=2

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3 years ago
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Natasha2012 [34]

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Step-by-step explanation:

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2 years ago
I need help with my homework :/
beks73 [17]
I HAVE THE FOLLOWING APPROACH
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WE ADD ALL THE NUMBERS AND GET 142+A+B= 17*10
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3 years ago
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