Question

Find the perimeter of a rectangle if the length is 6y + 10 and the width is y - 3

Answer 1

Step-by-step explanation:

Given that,

• Length = 6y + 10
• Width = y – 3

$\implies \sf Perimeter = 2(L + W) \\ \implies \sf P= 2(6y + 10 + y - 3) \: units \\ \implies \sf P= 2(7y +7) \: units \\ \implies \red{\sf P= 14y + 14 \: units}$

Therefore, perimeter is (14y + 14) units.