Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet,
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :
Putting all the values,
.....(1)
For maximum height, put
Put t = 1.875 in equation (1)
So, the maximum height reached by the ball is 61.25 m.
Answer:
The time interval when is at
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :
So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between
The schematic free body graphical representation of the above illustration was attached in the file below and the point when is at 4 is obtained in the parabolic curve.
So, is at
Taking the integral of the time interval in order to determine the distance; we have:
distance =
=
= By using the Scientific calculator notation;
distance = 106.109 m
