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iris [78.8K]
3 years ago
14

How to identify whether is it solid/liquid/gas/aqeous?​

Chemistry
1 answer:
MA_775_DIABLO [31]3 years ago
4 0

Answer:

You have to know what the three sates of matter are

Explanation:

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PLEASE HELP!!! The gold foil Rutherford used in his scattering experiment had a thickness of approximately 4×10−3 mm . If a sing
Ilya [14]

Answer:

16 atoms thick

Explanation:

4*10-3= 37

2.9*10-8=21

37-21=16

3 0
3 years ago
Read 2 more answers
Pls help me it detects if it’s right or wrong
Alona [7]
Number 2 is Blackland Prairies

The Blackland Prairies region is named for the deep, fertile black soils that characterize the area.
7 0
3 years ago
I don't understand any of these
77julia77 [94]
Ok well whats the questions
3 0
3 years ago
What is the daughter nucleus (nuclide) produced when 90sr undergoes beta decay by emitting an electron? replace each question ma
Mars2501 [29]
Beta decay by emitting an electron is called as β⁻ decay. when this happens, a neutron of the element converts into a proton by emitting an electron. Hence, the mass of daughter nucleus is same as parent atom but atomic number/number of protons is higher by 1 than atomic number of parent atom.

Sr has atomic number as 38.

After β⁻ decay, the daughter nucleus will have atomic number as 38 + 1 = 39.
Hence, the daughter nucleus should be Y (Yttrium). Formula is,

₃₈⁹⁰Sr → ₃₉⁹⁰Y + ₋₁⁰β + energy

6 0
4 years ago
If your front lawn is 18.0 feet wide and 20.0 feet long. And each square foot of lawn accumulates 1450 new snow flakes every min
creativ13 [48]
To solve this problem, we begin by first calculating the area of the front lawn. The length and width of the lawn was given and the area of a rectangle is given by the formula: Area = length x width. Thus, the area of the front lawn can be obtained by multiplying 18 ft by 20 ft, wherein we get 360 ft^2 as the area. 

Second, the problem indicated that each square foot of lawn accumulates 1450 new snow flakes per minute. This can be translated into the expression 1450 snow flakes/ (minute·ft^2). In this way, we can convert it to units of mass (kg). Afterwards, we simply need to multiply it to the area of the lawn and convert minute to hour. The following expression is then used:

1450 snow flakes/ (minute·ft^2) x 1.90 mg/snow flake x 1 g/1000 mg x 1kg/1000 g x 360 ft^2 x 60 minutes/hour = 59.508 kg snow flake/hour

It is then calculated that 59.508 kg of snow flake accumulates in the lawn every hour. 
 
6 0
3 years ago
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