B 2
is which shell are the valence electrons of the elements in period 2 found
Given :
A compound has a molar mass of 129 g/mol .
Empirical formula of compound is C₂H₅N .
To Find :
The molecular formula of the compound.
Solution :
Empirical mass of compound :

Now, n-factor is :

Multiplying each atom in the formula by 3 , we get :
Molecular Formula, C₆H₁₅N₃
Ends....................?
<span>Same answer, different setup. We know that the sum of the oxidation numbers is zero for a compound and the ionic charge for a polyatomic ion, and we know that sulfite ion is -2.
Create an algebraic equation by multiplying the subscripts times the oxidation number of a single element.
+x -6 = -2
+x -2
S O3
Solve for x
x = +4</span>