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Naya [18.7K]
3 years ago
8

Which of the following is a solution to 2cos^2x– 2 = 0 ?

Mathematics
2 answers:
Sphinxa [80]3 years ago
8 0

Answer:

A and C

Step-by-step explanation:

Given

2cos²x - 2 = 0 ( add 2 to both sides )

2cos²x = 2 ( divide both sides by 2 )

cos²x = 1 ( take the square root of both sides )

cos x = ± \sqrt{1} = ± 1

cos x = 1 ⇒ x = cos^{-1}(1) = 0°

cos x  = - 1 ⇒ x = cos^{-1}(- 1) = 180°

gogolik [260]3 years ago
5 0

Answer:

2 possible results

0° and 180°

Step-by-step explanation:

2cos² x– 2 = 0  (add 2 to both sides)

2cos² x = 2  (divide both sides by 2)

cos² x = 2/2

cos² x = 1

cos x = ±√1

cos x = ±1

because the range of x is not stated, there are 2 possible results for x  that will cause cos x to be either 1 or -1

0° and 180°

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<u>Solution:</u>

Given that, we have to explain Is a relation always a function and is a function always a relation

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So, we can say that function is a type of relation.

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