Answer:
See figure 1 and 2
Explanation:
In this case, we can start with the general reaction. Acetanilide with bromine in acetic acid we will produce <u>p-bromo-acetanilide</u> (See figure 1).
In the reaction mechanism, we have as first step the attack of the double bond in the benzene ring to one of the Br atoms in bromine () and a positive carbon will be produced in benzene. This positive charge can be moved inside of the benzne ring producing the r<u>esonance structures A, B and D</u>. Resonance structure C is produced when a double bond is generating between the "N" atom and the carbon in the benzene ring.
The final step in the mechanism is when we remove the "H" atom in structure A to produce again the double bond.
See figure 2
I hope it helps!
<h2>
Answer:</h2>
[4] - 3/2 - 7/4 => - 6 - 7 /4 => - 13/4 => - 3¼.
<u>Correct choice</u> - ✔ [C] - 3¼.
[6] (a) - 729 = - 9³.
(e) 216 = 6³.
Answer:
An observation which requires measurement is called Quantitative.
Answer:
7.78×10¯³ mole
Explanation:
From the question given above, the following data were obtained:
Volume (V) = 75 mL
Pressure (P) = 255 kPa
Temperature (T) = 22.5 °C
Number of mole (n) =?
Next, we shall convert 75 mL to L. This can be obtained as follow:
1000 mL = 1 L
Therefore,
75 mL = 75 mL × 1 L / 1000 mL
75 mL = 0.075 L
Next, we shall convert 22.5 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
Temperature (T) = 22.5 °C
Temperature (T) = 22.5 °C + 273
Temperature (T) = 295.5 K
Finally, we shall determine the amount of oxygen molecules present in steel calorimeter. This can be obtained as follow:
Volume (V) = 0.075 L
Pressure (P) = 255 kPa
Temperature (T) = 295.5 K
Gas constant (R) = 8.314 KPa.L/Kmol
Number of mole (n) =?
PV = nRT
255 × 0.075 = n × 8.314 × 295.5
19.125 = n × 2456.787
Divide both side by 2456.787
n = 19.125 / 2456.787
n = 7.78×10¯³ mole
Thus, amount of oxygen molecules present in steel calorimeter is 7.78×10¯³ mole
Answer: B
Explanation: because it just makes sense