Answer:
Keq = 1.17 × 10²⁰
Explanation:
Let's consider the following redox reaction.
Cu²⁺(aq) + Ni(s) → Cu(s) + Ni²⁺(aq)
We can identify 2 half-reactions.
Cathode (reduction): Cu²⁺(aq) + 2 e⁻ → Cu(s) E°red = 0.337 V
Anode (oxidation): Ni(s) → Ni²⁺(aq) + 2 e⁻ E°red = -0.257 V
The standard cell potential (E°) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.
E° = E°red, cat - E°red, an = 0.337 V - (-0.257V) = 0.594 V
We can calculate the equilibrium constant (Keq) using the following expression.
where,
n are the moles of electrons transferred
The number of molecules in one mole of any substance is equal to Avagadro's number
Avagadro's number is 6.023 X 10²³
Thus
1 mole = 6.023 X 10²³ molecules
for ammonia we are provided with three moles
so to obtain the total number of molecules of ammonia in three moles we will multiply the Avagadro's number with three
total molecules = 3 X 6.023 X 10²³
Total molecules of ammonia = 18.069 X 10²³
In scientific notation
Total molecules of ammonia = 1.8069 X 10²⁴ = 1.81 X 10²⁴
Answer:
Three to four weeks
Explanation: I had cranberries and In like four weeks my mom forced me to get rid of them. They do stink when rotten ;(
Answer:
2.coefficient how many molecules of Aluminum hydroxide there are
A replacement reaction which is where the positively charged portion of one of the reactants takes on the negatively charge portion of the other reactant without giving any portion of itself to the other to form products.
