Answer:
5.00 g calcium chloride in 95.0 g of water. Solute? ... (4 pts) Calculate the grams of copper (II) nitrate needed to make 100.0 mL of a 3.50 M solution
Explanation:
A. bar graph would be the closest
Answer:
a. K⁺
b. Se²⁻
Explanation:
Isoelectronic species are those that have the same number of electrons.
a.
Ar has 18 electrons. K has 19 electrons, so when it loses 1 electron to form K⁺, it is isoelectronic with Ar.
b.
Kr has 36 electrons. Se has 34 electrons, so when it gains 2 electrons to form Se²⁻, it is isoelectronic with Kr.
Answer:
2.0 M
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 2.93 g
- Volume of the solution: 0.025 L
Step 2: Calculate the moles corresponding to 2.93 g of NaCl
The molar mass of NaCl is 58.44 g/mol.
2.93 g × 1 mol/58.44 g = 0.0501 mol
Step 3: Calculate the molarity of the solution
Molarity is equal to the moles of solute divided by the liters of solution.
M = 0.0501 mol/0.025 L = 2.0 M
Answer:
0,218 moles
Explanation:
I will first explain how many liters is 256ml, that is 0,256 l.
because the m stands for milli which is a factor of 1000 -> (256 ml / 1000 = 0,256 l)
To calculate the amount of moles you multiply the volume with the concentration. So 0,256l x 0,855M = 0,218 moles.
