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horsena [70]
3 years ago
14

What best describes the kinetic energy of two gas particles before and after a collision?

Chemistry
1 answer:
saul85 [17]3 years ago
7 0
Kinetic energy is the energy possessed by the body when in motion. It is calculated by 1/2mv² where m is the mass of the body and v is the velocity.
Baring in mind that energy can not be created or destroyed but can only be transformed from one form to another (law of conservation of energy) then when two bodies collide the total kinetic energy of the two particles stays the same (kinetic energy is preserved). This is in the case of perfectly elastic collision, however, during inelastic collisions the kinetic energy is transformed to other forms of energy such as heat, sound and energy used in bond breakage.
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Put the elements in order from the highest electronegativity at the top of your list, to the lowest at the bottom. Germanium (Ge
Illusion [34]
Br
Se
As
Ge
Ga
Rb
Elements in the top right corner of the periodic table have the highest electronegativity. Elements on the right side have a higher electronegativity than those on the left, same with the ones on the top in comparison to those on the bottom. 
8 0
3 years ago
Identify the element represented by 8135X.
sashaice [31]

Answer:

I wish I knew but I don't hope u get the answer

4 0
3 years ago
A chemist wants to make 6.5 L of a 0.340 M CaCl2 solution. Part A What mass of CaCl2 (in g) should the chemist use? Express your
katovenus [111]

Answer:

The answer to your question is 245 grams

Explanation:

Data

Volume 6.5 L

Molarity = 0.34

mass of CaCl₂ = ?

Process

1.- Calculate the molar mass of CaCl₂

molar mass = (1 x 40) + (2 x 35.5)

                   = 40 + 71

                   = 111 g

2.- Convert the grams to moles

                       111 g of CaCl₂ -------------- 1 mol

                         x                   ---------------0.34 mol

                         x = (0.34 x 111) / 1

                         x = 37.74 g

3.- Calculate the total mass

                        37.74 g ------------------ 1 L

                            x        ------------------ 6.5 L

                            x = (6.5 x 37.74) / 1

                            x = 245.31

3 0
3 years ago
The outline of a partial periodic table is shown.
vova2212 [387]

Answer:

I think section #3

Explanation:

When i was in science class in my memory it was always in that area

4 0
3 years ago
Read 2 more answers
The standard enthalpy of formation for glucose [c6h12o6(s)] is −1273.3 kj/mol. what is the correct formation equation correspond
balu736 [363]
The standard formation equation for glucose C6H12O6(s) that corresponds to the standard enthalpy of formation or enthalpy change ΔH°f = -1273.3 kJ/mol is 
     C(s) + H2(g) + O2(g) → C6H12O6(s)
and the balanced chemical equation is 
     6C(s) + 6H2(g) + 3O2(g) → C6H12O6(s)

Using the equation for the standard enthalpy change of formation 
     ΔHoreaction = ∑ΔHof(products)−∑ΔHof(Reactants)
     ΔHoreaction = ΔHfo[C6H12O6(s)] - {ΔHfo[C(s, graphite) + ΔHfo[H2(g)] + ΔHfo[O2(g)]}

C(s), H2(g), and O2(g) each have a standard enthalpy of formation equal to 0 since they are in their most stable forms:
     ΔHoreaction = [1*-1273.3] - [(6*0) + (6*0) + (3*0)]
                           = -1273.3 - (0 + 0 + 0)
                           = -1273.3
8 0
3 years ago
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