Assuming that the probability of boys and girls is equal (in reality slightly more boys than girls are born), the probability is 1/2, simply because the older girl's gender is given and therefore not a part of the probability.
This question comes from the 'boy or girl paradox', a.k.a. the Mrs Smith Problem.
Answer:
Step-by-step explanation:
Let the number of dimes be d and quarters be q
<u>The value is $8.80 = 880¢, so:</u>
- 10d + 25q = 880 ⇒ 2d + 5q = 176
<u>If the dimes were quarters and the quarters were dimes, the coins' total value would be $7.30 or 730¢</u>
- 25d + 10q = 730 ⇒ 5d + 2q = 146
<u>Now we have 2 equations. Solving the system by elimination, subtract 5 times the second equation from twice the first equation:</u>
- 2(2d + 5q) - 5(5d + 2q) = 2(176) - 5(146)
- 4d - 25d = -378
- -21d = -378
- d = -378/-21
- d = 18
Answer:
2
Step-by-step explanation:
the rate of change is Rise/ Run
= Δy / Δx
= (y2 – y1) / (x2 – x1)
= (1 - (-1))/(-1 - (-2))
=2/1
=2
Answer:5.4 km
Step-by-step explanation:
Let b be the base. Then
b+16=1/2 (6b)
3b=b+16
2b=16
b=8
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