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Kay [80]
3 years ago
9

1) Is y=-3 a solution to the equation-3x^2=-27

Mathematics
1 answer:
sergey [27]3 years ago
8 0

Answer:

1)Yes

2)No

Step-by-step explanation:

1) 3x^2 = -27

3 (-3)^2 = -27

Once you substitute your value in for x, you can follow the rule <u>PEMDAS</u> to solve the equation.

3 (-9) = -27

-27 =-27

2) 10 - 5x = y

In an ordered pair, the first number is x and the second number is y.

10 - 5 (-4) = 10

10 - 20 = 10

-10 = 10

-10 ≠ 10

PEMDAS: A rule that states solving an equation by the order of operations:

Parentheses

Exponents

Multiplication

Division

Addition

Subtraction

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HELPPPPPPPPPPPPPPPPPPPPPPP T^T PLEASE ANSWER!!!!
likoan [24]

Answer:

7 miles per hour.

Step-by-step explanation:

Right now, the relationship in the problem represents 3\frac{1}{2} miles in  hours. To find out what the unit rate is (number of miles per mile), we need to multiply both sides of the equation show BeLoW:

3\frac{1}{2} = \frac{1}{2}

7 miles = 1 hour

Therefore, Doug's average speed in miles per hour is 7 (7 miles per hour).

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5 0
3 years ago
"A curtain manufacturer uses a 90-yard roll of material to make 77 identical curtains. There was 7.75 yards of material left ove
goblinko [34]

Answer:

1.06818181 there you go

7 0
3 years ago
Read 2 more answers
Complete the factoring<br> 7y+42=7()
stiks02 [169]
7y + 42 = 7(y + 6)

Hope this helps.
3 0
3 years ago
Read 2 more answers
An astronaut on the moon throws a baseball upward. The astronaut is 6 ft 6 in tall, and the initial velocity of the ball is 40 f
weqwewe [10]

Answer:

t = 0.293 s and 14.52 s

Step-by-step explanation:

The heights of the ball in feet is given by the equation as follows :

S = -2.7t^2+40t+6.5

Where t is the number of seconds after the ball was thrown.

We need to find is the ball 18 ft above the moon's surface.

Put S = 18 ft

-2.7t^2+40t+6.5=18\\\\-2.7t^2+40t=18-6.5\\\\-2.7t^2+40t-11.5=0

It is a quadratic equation. Its solution is given by :

t=\dfrac{-40+\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)},\dfrac{-40-\sqrt{40^{2\ }-4\left(-2.7\right)\left(-11.5\right)}}{2\left(-2.7\right)}\\\\t=0.293\ s,14.52\ s

So, the ball is at first 0.293 s and then 14.52 s above the Moon's surface.

8 0
3 years ago
in a class of 28 sixth graders all but one of the students are 12 years old. witch two data measurements are the same for the st
Doss [256]
Out of 28 kids there is one that isnt 12
so 27 kids are 12 years old
1 isnt
concluding that, that 6th grade might be 11
so 1 out of 28
1:28


5 0
3 years ago
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