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3 years ago

What is the best way to cut a taper

Engineering

2 answers:

jeyben [28]3 years ago

6 0

Answer:

with scissors

Explanation:

uranmaximum [27]3 years ago

5 0

Answer :
With scissors

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A 20 mm diameter rod made of ductile material with a yield strength of 350 MN/m2 is subjected to a torque of 100 N.m, and a bend

vodka [1.7K]

Answer:

a) 42.422 KN

b) 44.356 KN

Explanation:

Given data :

Diameter = 20 mm

yield strength = 350 MN/m^2

Torque ( T ) = 100 N.m

Bending moment = 150 N.m

Determine the value of the applied axial tensile force when yielding of rod occurs

first we will calculate the shear stress and normal stress

shear stress ( г ) = Tr / J = [( 100 * 10^3) * 10 ] / $\pi /32$ * ( 20)^4

= 63.662 MPa

Normal stress( Гb + Гa ) = MY/ I + P/A

= [( 150 * 10^3) * 10 ] / $\pi /32$ * ( 20)^4 + 4P / $\pi * 20^2$

= 190.9859 + 4P / $\pi * 20^2$ MPa

a) Using MSS theory

value of axial force = 42.422 KN

solution attached below

b) Using MDE theory

value of axial force = 44.356 KN

solution attached below

5 0

3 years ago

I just need help on problem B

Komok [63]

The problem b is An example of a law being implemented by bureaucratic agency is____
A. Congress passing legislation by major vote
B. OSHA deciding how hazardous substance should be stored
C. the USPS delivering mail throughout the country
D. A watchdog group blowing the whistle on government corruption

8 0

3 years ago

SRSS is a method used in responce spectram analysis

VMariaS [17]

Answer:

Modal analysis is performed to identify the modes, and the response in that mode can be picked from the response spectrum. These peak responses are then combined to estimate a total response. A typical combination method is the square root of the sum of the squares (SRSS) if the modal frequencies are not close.

5 0

3 years ago

A piston–cylinder assembly contains 5 kg of air, initially at 2.0 bar, 30 C. The air undergoes a process to a state where the pr

Ainat [17]

Answer: wor done is 145. 06kJ

Heat transfer is 135.53kJ

Explanation:

No of moles of air = mass/molar mass = 5000g/28gmol^-1 = 172.65mol

P1 = 2bar =2*101300 =202600pa

T1 = 30° +273k = 303k

P2 =p1 = 202600pa

V2 =? T2 =?

Using pV = nRT

R = 8.314 PA m^3 mol^-1 k^-1

V1 = (172.65*8.314*303)/202600

V1 = 2.146m^3

For second state, 1.5pv = const = P1V1

V2 = (202600*2.146)/(1.5*202600)

V2 = 1.43m^3

Volume change = 2.146 - 1.43 =0.715m^3

Word done = pressure* volume change

W = 202600*0.716 = 145061.6J

= 145.061kJ

Using V1/T1 = V2/T2

T2 = V2T1/V1

=(1.43*303)/2.146 = 201.9k

For internal energy U

U = nCv*(T2 - T1)

*CV is the heat capacity at const. vol approximately 0.718J mol^-1 k^-1

U = 172.65*0.718*(201.9-303)

U = -12532.6J = -12.532kJ

The -ve means the system lost internal energy.

Q = U+W = total heat energy of system

Q = - 12.532+145.061 = 132.52 kJ

7 0

4 years ago

Find the resultant of the force system on the body OABC as shown .find the points where the resultant will cut the X and Y axis?

MAXImum [283]

Explanation:

the resultant force =

$\sqrt{} {x}^{2} + {y}^{2}$

5 0

3 years ago