Answer:
The expected settlement for the pile group using the given information is 19.92mm or 0.79 inch
Explanation:
In this question, we are asked to calculate the expected settlement for the pole group given some information.
Please check attachment for complete solution and step by step explanation
Answer:
(a) the subtransient current through the breaker in per-unit and in kA rms = 71316.39kA
(b) the rms asymmetrical fault current the breaker interrupts, assuming maximum dc offset. = 152KA
Explanation:
check the attached files for explanation
Answer:
18.75in
Explanation:
Modulus of elasticity = Stress/Strain
Since stress = Force/Area
Given
Force = 1000lb
Area = 0.75sqin
Stress = 1000/0.75
Stress = 1333.33lbsqin
Strain
Strain = Stress/Modulus of elasticity
Strain = 1333.33/5,000,000
Strain = 0.0002667
Also
Strain = extension/original length
extension = 0.005in
Original length = extension/strain
Original length = 0.005/0.0002667
Original length = 18.75in
Hence the original length of the rectangular bar is 18.75in
Answer:
I forget the word for it, but probably the guys who set up the power lines in the city.
Explanation: