Step-by-step explanation:
Any complex number is of the form: 
where a is real part and B is imaginary part.
Therefore, in given complex number: 
7 is real part.
is imaginary part.
Hence, first two options are correct.
Last two options are incorrect because of the following reasons:
is coefficient of 
& not 
Given number is a difference of a real number and imaginary number & not a sum of a real number and imaginary number.
Answer:
2x^2 = 6x - 5.
-x^2 - 10x = 34.
These have only complex roots/
Step-by-step explanation:
3x^2 - 5x = -8
3x^2 - 5x + 8 = 0
There are complex roots if the discriminant 9b^2 - 4ac) is negative.
Here the discriminant D = (-5)^2 - 4*-5*8 = 25 + 160
This is positive so the roots are real.
2x^2 = 6x - 5
2x^2 - 6x + 5 = 0
D = (-6)^2 - 4*2*5 = 36 - 40 = -4
So this has no real roots only complex ones.
12x = 9x^2 + 4
9x^2 - 12x + 4 = 0
D = (-12)^2 - 4*9 * 4 = 144 - 144 = 0.
- Real roots.
-x^2 - 10x = 34
x^2 + 10x + 34 = 0
D = (10)^2 - 4*1*34 = 100 - 136 = -36.
No real roots = only complex roots.
Hey there!
2 + 1.25f = 10 - 2.75f
Add 2.75f to both sides.
1.25f + 2.75f = 4f
4f + 2 = 10
Subtract 2 from both sides.
4f = 8
Divide both sides by 4 to solve for f.
f = 2
I hope this helps!
Answer:
7 units
Step-by-step explanation:
=7
