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REY [17]
2 years ago
6

Which step is the same when constructing an inscribed regular hexagon and an inscribed equilateral triangle?.

Mathematics
1 answer:
Naddik [55]2 years ago
7 0

Step is the same when constructing an inscribed regular hexagon and an inscribed equilateral triangle is shown below:

<h3 /><h3>What is construction?</h3>

Geometric construction is the process of drawing a geometrical figure using two geometrical instruments, a compass, and a ruler.

Construction of an inscribed regular hexagon

1) Set compass width to the radius of the circle

2) Make an arc on the circle with the set radius.

3) From the previous arc draw another arc with the same radius.

4) Continue this process for the other vertex.

5) Connect all the vertices.

Construction of an inscribed equilateral triangle

1) Set compass width to the radius of the circle

2) Make an arc on the circle with the set radius.

3)From the previous arc draw another arc with the same radius.

4)Continue this process for the other vertex.

5) Connect the every other vertices point by drawing  a line between every other adjacent vertex point to form an inscribed equilateral triangle.

Learn more about construction here:

brainly.com/question/791518

#SPJ1

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your answer is 56


3 0
3 years ago
What is 10 less than 14 in algebraic expression?
Cerrena [4.2K]

14-10=? less than indicates that a minus sign is needed.

7 0
3 years ago
The sum of three different numbers is 18. If every number is a prime number, what are the three numbers?
alexdok [17]
The sum of three primes is 18 so they must all be smaller than 18 as well.

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2,3, and 13

2,5, and 11

There are two solutions...


3 0
2 years ago
Read 2 more answers
A line passes through (3, -2) and (6,2). Write an equation for the line in point-slope form.
snow_lady [41]

Answer:

4x - 3y -18 = 0 or y = 4x/3 - 6

Step-by-step explanation:

We will have to find the slope of the line first

The formula for slope:

m =\frac{y_{2}- y_{1} }{x_{2} -x_{1} } \\m= \frac{-2-2}{3-6}\\ =\frac{-4}{-3}\\ =\frac{4}{3}

The standard form of equation of a line is:

y = mx + b

We know m,

So the equation will be:

y= \frac{4}{3}x+b

We have to find the value of b, for that we will put any one of the point in the equation

So, putting (6,2)

2 = 4/3 * 6 + b

2 = 8 +b

b = -6

Putting the value of m and b in the standard form of equation of line,

y = mx + b\\y = \frac{4}{3}x+(-6)\\y = \frac{4}{3} x - 6\\Multiplying\ both\ sides\ by\ 3\\3y = 4x - 18\\4x - 3y -18 = 0 ..

7 0
3 years ago
Line j has a slope of − 2. Line d is perpendicular to line j and passes through the point( − 8 , 3 ).  Write the equation for
Zina [86]

Answer:

The equation is: y = 1/2x + 7

Step-by-step explanation:

The slope of j is -2. The slope of a line perpendicular to line j has a negative inverse: 1/2. The point is (-8, 3).

Use the point slope form of the equation:

y - y1 = m(x - x1)

Substitute:

y - 3 = 1/2(x - (-8))

y - 3 = 1/2x + 4

y = 1/2x + 4 + 3

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Proof:

Solve for f(x) when x = -8.

f(x) = 1/2x + 7

f(-8) = 1/2(-8) + 7

= -8/2 + 7

= -4 + 7

= 3, giving the point (-8, 3)

4 0
3 years ago
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