For this case, we have that by definition, the circumference of a circle is given by:
Where:
d: Is the diameter of the circle given by 2r, that is, twice the radius.
If we have a circle with a diameter equal to 8cm, then the circumference is given by:
ANswer:
Option C
Answer:
Step-by-step explanation:
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solucion
Volumen de un cilindro: es igual al área de la tapa por la altura del mismo
A = πD² * h / 4
Lata grande y lata pequeña
Para la lata grande, el diámetro y la altura han aumentado un 20%.
Lata pequeña:
d = 4 cm
h = 3 cm
A 1 = π * (4) ² * 3/4
A1 = 37,70 cm²
Lata grande:
d = 4 * 1,2 = 4,8 cm
h = 3 * 1,2 = 3,6 cm
A2 = π (4,8) ²3,6 / 4
A2 = 65,14 cm²
Si 37,7 representa el 100%
65,14 representación x
x = 170%
El incremento del volumen es de un 70%
Answer:
Step-by-step explanation:
Given the expression cosec (x) = 4 and tan(x)< 0
since cosec x = 1/sinx
1/sinx = 4
sinx = 1/4
From SOH, CAH TOA
sinθ = opposite/hypotenuse
from sinx = 1/4
opposite = 1 and hypotenuse = 4
to get the adjacent, we will use the Pythagoras theorem
adj² = 4²-1²
adj² = 16-1
adj ²= 15
adj = √15
cosx = adj/hyp = √15/4
tanx = opposite/adjacent = 1/√15
since tan < 0, then tanx = -1/√15
From double angle formula;
sin2x = 2sinxcosx
sin2x = 2(1/4)(√15/4)
sin2x = 2√15/16
sin2x = √15/8
for cos2x;
cos2x = 1-2sin²x
cos2x = 1-2(1/4)²
cos2x = 1-2(1/16)
cos2x= 1-1/8
cos2x = 7/8
for tan2x;
tan2x = tanx + tanx/1-tan²x
tan2x = 2tanx/1-tan²x
tan2x = 2(-1/√15)/1-(-1/√15)²
tan2x = (-2/√15)/(1-1/15)
tan2x = (-2/√15)/(14/15)
tan2x = -2/√15 * 15/14
tan2x = -30/14√15
tan2x = -30/7√15
rationalize
tan2x = -30/7√15 * √15/√15
tan2x = -30√15/7*15
tan2x = -2√15/7
√(2x+4)=16 square both sides
2x+4=256 subtract 4 from both sides
2x=252 divide both sides by 2
x=126
Answer:
3 sides
Step-by-step explanation:
Two sides will have the same angle measurement while the third angle will be different.
