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3 years ago

The coolor below holds 10 gallons. How many quarts will the jug hold?

Mathematics

1 answer:

kiruha [24]3 years ago

6 0

Can we get a picture?

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Fine The Slope Of Each Line Defined Below And Compare Their Values.

victus00 [196]

Answer:

slope of line A= 5/3

slope line B=3/5

they are reciprocals 5/3>3/5

Step-by-step explanation:

the intercepts are 0,5 and -3,0 so 0+3/5+0= the slope

3/5 is the slope

4 0

3 years ago

Solve for the missing hypotenuse. Round your answers to the nearest tenth.<br><br> Help me ASAP!!!

andreyandreev [35.5K]

Answer:

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Step-by-step explanation:

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3 years ago

Higher Order Thinking.

defon

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3 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

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3 years ago

16) (5x +2)(7x - 2)<br> Ayoo can someone answer that man

algol [13]

(16) (12) (12) is the answer I think

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3 years ago