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Elena L [17]
3 years ago
12

27272727272727727272782828282

Chemistry
2 answers:
sertanlavr [38]3 years ago
8 0
I think the answer would be 2.48% = 277.99% hope this helps!!
aliya0001 [1]3 years ago
5 0
The answer isss ,jhkudxhbkhvblihfb9fjenv
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How many moles of KCl are contained in this solution?<br><br>0.486 L of a 2.0 M KCl solution
Vika [28.1K]

Answer:

0.972mol

Explanation:

Given parameters:

Volume of Solution of KCl = 0.486L

Molarity = 2.0M

Unknown:

Number of moles of KCl in solution = ?

Solution:

To find the number of moles of KCl in this solution, use the expression below;

  Number of moles  = molarity x volume

Insert the parameters and solve;

  Number of moles  = 0.486 x 2  = 0.972mol

5 0
3 years ago
The gases in air dissolve in water. What would be one way to reduce the amount of a gas dissolved in water?
pav-90 [236]
B would be the best answer
7 0
3 years ago
A. Airplanes typically fly at an altitude of about 10,000 meters. At this altitude the atmospheric pressure is significantly les
tangare [24]

Answer:

The new volume of the air inside when the cabin is pressurized to 75 kPa is 37818.\overline 6 m³

Explanation:

The given 747 airplane parameters are;

The volume of air in the airplane, V₁ = 28,000 m³

The pressure of the air on the ground, P₁ = 101.3 kPa

The pressure of the air once it is in flight, P₂ = 75 kPa

Let V₂ represent the new volume of the air inside when the cabin is pressurized to 75 kPa

Boyle's Law states that the pressure of a given mass of air is inversely proportional to its volume at constant temperature

Therefore, by Boyle's law, we have;

P ∝ 1/V and P₁·V₁ = P₂·V₂

Which gives;

V₂ = P₁·V₁/P₂

Substituting the known values, we get;

V₂ = 101.3 kPa × 28,000 m³/(75 kPa) = 37818.\overline 6 m³

The new volume of the air inside when the cabin is pressurized to 75 kPa = V₂ = 37818.\overline 6 m³.

8 0
3 years ago
Caleb is an inventor who has designed a new kind of fishing net. He is looking for a strong, flexible material that can be used
UkoKoshka [18]

Answer:

Its B Nylon

Explanation:

i just took the quiz and got it right.

5 0
3 years ago
Read 2 more answers
How many moles are present 560.0 g of iron (lll) sulfate
xxMikexx [17]

Answer:

1.400 mol

Explanation:

To convert grams to moles, you will need the molar mass.  The molar mass of iron(iii) sulfate is 399.88 g/mol.  Divide grams by the molar mass to find moles.

(560.0 g)/(399.88 g/mol) = 1.400 mol

There are 1.400 mol present in 560.0 g of iron(iii) sulfate.

3 0
4 years ago
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