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pochemuha
3 years ago
10

What is the mass of the solute in 250 mL of 0.122 mol/L potassium phosphate?

Chemistry
1 answer:
inysia [295]3 years ago
8 0

Answer:

What is the mass of solute, in grams, in 250.00 mL of a 0.0125 M solution of KMnO4? Moles KMnO4 = M × V = 0.0125 M × 0.250 L = 3.13 × 10-3 mol KMnO4 grams KMnO4 = 3.13 × 10-3 mol KMnO4 × ( 158.03 g KMnO4/1 mol KMnO4) = 0.495 g 4.

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Answer:

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Explanation:

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For the body-centered cubic unit cell, we have 8 corners again shared each by 8 lattices as in the simple cubic plus we have one atom  in the center of the cubic lattice. Therefore, the number of atoms in the body -centerd unit cell is two:

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8 corner x 1/8 atom/corner + 6 faces x 1 atom/face = 4 atoms/unit cell

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