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san4es73 [151]
2 years ago
10

I need help on this may u help me?

Chemistry
1 answer:
sergij07 [2.7K]2 years ago
7 0

Answer:

just go to googel and it will tell you

Explanation:

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A piece of wood near a fire is at 23°C. It gains 1,160 joules of heat from the fire and reaches a temperature of 42°C. The speci
Molodets [167]

Answer:

35.578g or 36g if you round

Explanation:

Q=mc ∆∅ where ∅ is temperature difference

1160= m x 1.716 x (42-23)

m = 1160/ 1.716 x19

m=35.578g

m = 36g to nearest whole number

6 0
3 years ago
What is the result of a neutralization reaction between nitric acid (HNO3) and potassium hydroxide (KOH)?
scZoUnD [109]
HNO3+KOH = H2O+KNO3 . When nitric acid react with pottasuim hydroxide, the reaction will produce water (H20) and pottasuim trioxonitrate
3 0
2 years ago
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The changing of a substance from a liquid into a vapor or gas is called
sergejj [24]

Answer: Boiling and Evaporation: Evaporation is the change of a substance from a liquid to a gas. Boiling is the change of a liquid to a vapor, or gas, throughout the liquid.

Explanation: Boiling and Evaporation: Evaporation is the change of a substance from a liquid to a gas. Boiling is the change of a liquid to a vapor, or gas, throughout the liquid.

6 0
1 year ago
Does Monocercomonoides still meet the definition of a eukaryote? Why or why not?
KengaRu [80]

Answer:

Yes

Explanation:

They are a unique type of eukaryote because they lack an important organelle: mitochondria. Mitochondria are essential for producing cellular energy in most eukaryotic cells. However, due to its habitat, it is able to acquire energy from a process called  sulfur mobilization.

They are significant because they challenge the idea that eukaryotes need mitochondria to be classified as eukaryotic. However, they have other membrane-bound organelles such as a nucleus and Golgi apparatus, meaning they remain eukaryotic.

Research suggest they lost their mitochondria over time, rather than never having had them throughout their ancestry.

Because of all these reasons, they still meet the definition of a eukaryote.

6 0
3 years ago
7.00 of Compound x with molecular formula C3H4 are burned in a constant-pressure calorimeter containing 35.00kg of water at 25c.
beks73 [17]

Answer:

\Delta H_{f,C_3H_4}=276.8kJ/mol

Explanation:

Hello!

In this case, since the equation we use to model the heat exchange into the calorimeter and compute the heat of reaction is:

\Delta H_{rxn} =- m_wC_w\Delta T

We plug in the mass of water, temperature change and specific heat to obtain:

\Delta H_{rxn} =- (35000g)(4.184\frac{J}{g\°C} )(2.316\°C)\\\\\Delta H_{rxn}=-339.16kJ

Now, this enthalpy of reaction corresponds to the combustion of propyne:

C_3H_4+4O_2\rightarrow 3CO_2+2H_2O

Whose enthalpy change involves the enthalpies of formation of propyne, carbon dioxide and water, considering that of propyne is the target:

\Delta H_{rxn}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{f,C_3H_4}

However, the enthalpy of reaction should be expressed in kJ per moles of C3H4, so we divide by the appropriate moles in 7.00 g of this compound:

\Delta H_{rxn} =-339.16kJ*\frac{1}{7.00g}*\frac{40.06g}{1mol}=-1940.9kJ/mol

Now, we solve for the enthalpy of formation of C3H4 as shown below:

\Delta H_{f,C_3H_4}=3\Delta H_{f,CO_2}+2\Delta H_{f,H_2O}-\Delta H_{rxn}

So we plug in to obtain (enthalpies of formation of CO2 and H2O are found on NIST data base):

\Delta H_{f,C_3H_4}=3(-393.5kJ/mol)+2(-241.8kJ/mol)-(-1940.9kJ/mol)\\\\\Delta H_{f,C_3H_4}=276.8kJ/mol

Best regards!

7 0
2 years ago
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