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3 years ago

I need help on this may u help me?

Chemistry

1 answer:

sergij07 [2.7K]3 years ago

7 0

Answer:

just go to googel and it will tell you

Explanation:

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Diatomic iodine [I2] decomposes at high temperature to form I atoms according to the reaction I2(g)⇌2I(g), Kc = 0.011 at 1200∘C

umka2103 [35]

Answer:

The concentration of I at equilibrium = 3.3166×10⁻² M

Explanation:

For the equilibrium reaction,

I₂ (g) ⇄ 2I (g)

The expression for Kc for the reaction is:

$K_c=\frac {\left[I_{Equilibrium} \right]^2}{\left[I_2_{Equilibrium} \right]}$

Given:

$\left[I_2_{Equilibrium} \right]$ = 0.10 M

Kc = 0.011

Applying in the above formula to find the equilibrium concentration of I as:

$0.011=\frac {\left[I_{Equilibrium} \right]^2}{0.10}$

So,

$\left[I_{Equilibrium} \right]^2=0.011\times 0.10$

$\left[I_{Equilibrium} \right]^2=0.0011$

$\left[I_{Equilibrium} \right]=3.3166\times 10^{-2}\ M$

Thus, The concentration of I at equilibrium = 3.3166×10⁻² M

3 0

4 years ago

A student is asked to standardize a solution of barium hydroxide. He weighs out 0.978 g potassium hydrogen phthalate (KHC8H4O4,

Sav [38]

Answer:

(A) 0.129 M

(B) 0.237 M

Explanation:

(A) The reaction between potassium hydrogen phthalate and barium hydroxide is:

2HA + Ba(OH)₂ → BaA₂ + 2H₂O

Where A⁻ is the respective anion of the monoprotic acid (KC₈H₄O₄⁻).

We convert mass of phthalate to moles, using its molar mass:

0.978 g ÷ 156 g/mol = 9.27x10⁻³ mol = 9.27 mmol

Now we convert mmol of HA to mmol of Ba(OH)₂:

9.27 mmol HA * $\frac{1mmolBa(OH)_{2}}{2mmolHA}$ = 6.64 mmol Ba(OH)₂

Finally we calculate the molarity of the Ba(OH)₂ solution:

6.64 mmol / 35.8 mL = 0.129 M

(B) The reaction between Ba(OH)₂ and HCl is:

2HCl + Ba(OH)₂ → BaCl₂ + 2H₂O

So the moles of HCl that reacted are:

17.1 mL * 0.129 M * $\frac{2mmolHCl}{1mmolBa(OH)_2}$ = 4.41 mmol HCl

And the molarity of the HCl solution is:

4.41 mmol / 18.6 mL = 0.237 M

3 0

3 years ago

A sample of water vapor has a volume of 3.15 L, a pressure of 2.40 atm, and a temperature of 325 K. What is the new temperature,

lara31 [8.8K]

Answer:

The answer to your question is: T2 = 235.44 °K

Explanation:

Data

V1 = 3.15 L V2 = 2.78 L

P1 = 2.40 atm P2 = 1.97 atm

T1 = 325°K T2 = ?

Formula

$\frac{P1V1}{T1} = \frac{P2V2}{T2}$

Process

T2 = (P2V2T1) / (P1V1)

T2 = (1.97x 2.78x 325) / (2.40 x 3.15)

T2 = 1779.895 / 7.56

T2 = 235.44 °K

4 0

3 years ago

The blank of an element is the average mass of all isotopes of that element

Oxana [17]

Atomic mass is the answer

if u hav any more questions in chemistry ask me! I am very good at chemistry.

6 0

3 years ago

Plz help.chemissttrryy

Gelneren [198K]

Attached is the answer

3 0

3 years ago