Question

Given the function,g(x)=(x-1)/(x^2-1) , choose the correct value of x where the hole is located.

Answer 1

For this case we have the following function:
 g (x) = (x-1) / (x ^ 2-1)
 Rewriting we have:
 g (x) = (x-1) / ((x + 1) * (x-1))
 Canceling similar terms the function is:
 g (x) = 1 / (x + 1)
 We evaluate the value of x where the denominator is not defined:
 x + 1 = 0
 x = -1
 Answer:
 the correct value of x where the hole is located is:
 x = -1