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Natali [406]
3 years ago
11

Suppose the equation for line A is given by 2x = 5y – 25. If line A and B are perpendicular

Mathematics
1 answer:
Ludmilka [50]3 years ago
6 0

The required equation of line B is 2y+5x=-2

The equation of a line in point-slope form is expressed as:

y-y0 = m(x-x0)

m is the slope of the line

(x0, y0) is the point on the line

Given the line A expressed as:

2x = 5y – 25

Rewrite in standard form

5y = 2x + 25

y = 2/5 x + 5

The slope will be 2/5

The slope of the perpendicular line will be;

M = \frac{-1}{(2/5)}\\M = \frac{-5}{2}

Substitute the point (-6, 14) and slope -5/2 into the equation above to get the required equation of line B

y-14=-5/2(x+6)\\2(y-14) = -5(x+6)\\2y-28=-5x-30\\2y+5x=-30+28\\2y+5x=-2\\

Hence the required equation of line B is 2y+5x=-2

Learn more here: brainly.com/question/13140886

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I need help pleases I wil give brainyless
erica [24]

Answer: Let's start by writing down coordinates of all points:

A(0,0,0)

B(0,5,0)

C(3,5,0)

D(3,0,0)

E(3,0,4)

F(0,0,4)

G(0,5,4)

H(3,5,4)

a.) When we reflect over xz plane x and z coordinates stay same, y coordinate  changes to same numerical value but opposite sign. Moving front-back is moving over x-axis, moving left-right is moving over y-axis, moving up-down is moving over z-axis.

A(0,0,0)

Reflecting

A(0,0,0)

B(0,5,0)

Reflecting

B(0,-5,0)

C(3,5,0)

Reflecting

C(3,-5,0)

D(3,0,0)

Reflecting

D(3,0,0)

b.)

A(0,0,0)

Moving

A(-2,-3,1)

B(0,-5,0)

Moving

B(-2,-8,1)

C(3,-5,0)

Moving

C(1,-8,1)

D(3,0,0)

Moving

D(1,-3,1)

Hope this helps plz mark brainliest

Step-by-step explanation:

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Answer:

I think it's J.

Step-by-step explanation:

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Andrei [34K]

4x^2-25= (2x)^2-5^2=(2x-5)(2x+5)

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Answer:

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12 times 2.5 = 30

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