Question

Suppose the equation for line A is given by 2x = 5y – 25. If line A and B are perpendicular

Answer 1

The required equation of line B is 2y+5x=-2

The equation of a line in point-slope form is expressed as:

y-y0 = m(x-x0)

m is the slope of the line

(x0, y0) is the point on the line

Given the line A expressed as:

2x = 5y – 25

Rewrite in standard form

5y = 2x + 25

y = 2/5 x + 5

The slope will be 2/5

The slope of the perpendicular line will be;

$M = \frac{-1}{(2/5)}\\M = \frac{-5}{2}$

Substitute the point (-6, 14) and slope -5/2 into the equation above to get the required equation of line B

$y-14=-5/2(x+6)\\2(y-14) = -5(x+6)\\2y-28=-5x-30\\2y+5x=-30+28\\2y+5x=-2$

Hence the required equation of line B is 2y+5x=-2

Learn more here: brainly.com/question/13140886