We are already given with the mass of the Xe and it is 5.08 g. We can calculate for the mass of the fluorine in the compound by subtracting the mass of xenon from the mass of the compound.
mass of Xenon (Xe) = 5.08 g
mass of Fluorine (F) = 9.49 g - 5.08 g = 4.41 g
Determine the number of moles of each of the element in the compound.
moles of Xenon (Xe) = (5.08 g)(1 mol Xe / 131.29 g of Xe) = 0.0387 mols of Xe
moles of Fluorine (F) = (4.41 g)(1 mol F/ 19 g of F) = 0.232 mols of F
The empirical formula is therefore,
Xe(0.0387)F(0.232)
Dividing the numerical coefficient by the lesser number.
<em> XeF₆</em>
Equation: 2H₂ + O₂ → 2H₂O
Now, Given mass of Oxygen = 192 g
Molar mass of Oxygen = 16 g/mol
No. of moles in Oxygen = 16/192 = 0.0833
Now, for every mole of Oxygen, 2 mole of Hydrogen will form,
so, Number of moles of Hydrogen = 0.0833 * 2 = 0.167
Given mass = Number of Moles * Molar mass
Given mass = 0.167 * 2
m = 0.33 g
In short, Your Answer would be: 0.33 g
Hope this helps!
Answer:
62.07 %
Explanation:
Chemical Formula = (CH3)2CO = C3H6O
Mass of C = 12 g/mol
Mass of H = 1 g/mol
Mass of O = 12 g/mol
Mass of C3H6O = 3(12) + 6(1) + 16 = 58 g/mol
Total mass of C in Acetone = 12 * 3 = 36 g
Mass Percent of C = Total mass of C / Mass of Acetone * 100
Mass percent = 36 / 58 * 100
Mass percent = 62.07 %
Answer:
Oh it is convention
Explanation:
because the heat transfer is through fluids
Answer:
The answer is "
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Explanation:
Given equation:
Given value:
calculating the total pressure on equilibrium= 
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Calculating the Kp at 1100 K:
