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3 years ago

What happens when Mg forms an ionic bond?

Chemistry

2 answers:

makkiz [27]3 years ago

7 0

Answer:

it gains one electron and become a -2 anion...

it is the right answer..

above answer is right explanation

lara [203]3 years ago

6 0

When this reaction occurs, strong ionic bonds form between two oppositely charged particles (ions). Magnesium is a group II metal, and therefore has two electrons in it's highest energy level (or outermost electron shell). ... Therefore, they readily take up these two electrons to form negatively charged O2- ions

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Can anyone help with these ?

andriy [413]

Uh no I can’t help but, I hope you have a good day!

5 0

3 years ago

How many milliliters of a 0.285 M HCl solution are needed to neutralize 249 mL of a 0.0443 M Ba(OH)2 solution?

meriva

Answer:

$\large \boxed{\text{77.4 mL}}$

Explanation:

Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O

V/mL: 249

c/mol·L⁻¹: 0.0443 0.285

1. Calculate the moles of Ba(OH)₂

$\text{Moles of Ba(OH)$_{2}$} = \text{0.249 L Ba(OH)}_{2} \times \dfrac{\text{0.0443 mol Ba(OH)}_{2}}{\text{1 L Ba(OH)$_{2}$}} = \text{0.011 03 mol Ba(OH)}_{2}$

2. Calculate the moles of HCl

The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

$\text{Moles of HCl} = \text{0.011 03 mol Ba(OH)}_{2} \times \dfrac{\text{2 mol HCl}}{\text{1 mol Ba(OH)}_{2}} = \text{0.022 06 mol HCl}$

3. Calculate the volume of HCl

$V_{\text{HCl}} = \text{0.022 06 mol HCl} \times \dfrac{\text{1 L HCl}}{\text{0.285 mol HCl}} = \text{0.0774 L HCl} = \textbf{77.4 mL HCl}\\\\\text{You must add $\large \boxed{\textbf{77.4 mL}}$ of HCl.}$

8 0

4 years ago

The reaction of equal molar amounts of benzene, C6H6, and chlorine, Cl2, carried out under special conditions, yields a gas and

WINSTONCH [101]

Answer : The molecular formula of a compound is, $C_6H_5Cl_1$

Solution : Given,

Mass of C = 64.03 g

Mass of H = 4.48 g

Mass of Cl = 31.49 g

Molar mass of C = 12 g/mole

Molar mass of H = 1 g/mole

Molar mass of Cl = 35.5 g/mole

Step 1 : convert given masses into moles.

Moles of C = $\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{64.03g}{12g/mole}=5.34moles$

Moles of H = $\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{4.48g}{1g/mole}=4.48moles$

Moles of Cl = $\frac{\text{ given mass of Cl}}{\text{ molar mass of Cl}}= \frac{31.49g}{35.5g/mole}=0.887moles$

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C = $\frac{5.34}{0.887}=6.02\approx 6$

For H = $\frac{4.48}{0.887}=5.05\approx 5$

For Cl = $\frac{0.887}{0.887}=1$

The ratio of C : H : Cl = 6 : 5 : 1

The mole ratio of the element is represented by subscripts in empirical formula.

The Empirical formula = $C_6H_5Cl_1$

The empirical formula weight = 6(12) + 5(1) + 1(35.5) = 112.5 gram/eq

Now we have to calculate the molecular formula of the compound.

Formula used :

$n=\frac{\text{Molecular formula}}{\text{Empirical formula weight}}$

$n=\frac{112.5}{112.5}=1$

Molecular formula = $(C_6H_5Cl_1)_n=(C_6H_5Cl_1)_1=C_6H_5Cl_1$

Therefore, the molecular of the compound is, $C_6H_5Cl_1$

5 0

3 years ago

How many half -lives are required for three-fourths of the nuclei of an istope in a sample decay

timofeeve [1]

The half life of a radio-isotope is the amount of time required for half of the isotope to decay into a new element or sister isotope. One half life results in a 50% loss of radioisotope, and two half lives results in a 75% loss. For three-fourths of the nuclei to decay, two half-lives must pass.

7 0

3 years ago

Describe the different energy levels of electrons in an atom.

rosijanka [135]

Answer:

Explanation:

If it is at a higher energy level, it is said to be excited, or any electrons that have higher energy than the ground state are excited. They are then called degenerate energy levels.

6 0

3 years ago