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Aleonysh [2.5K]
3 years ago
12

0.5-0.3(-0.5--0.3) plssss

Mathematics
2 answers:
svlad2 [7]3 years ago
8 0

Answer:

0.44

Step-by-step explanation:

0.5-0.3 x0.2 (multiply)

0.5x0.06 = 0.44

(calculate)

ruslelena [56]3 years ago
4 0
ANSWER IS IN THE PICTURE!!
I GAVE YOU THE ANSWER IN
-DECIMAL
-FRACTION
-EXPO

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Fiesta28 [93]

The expression which is equivalent to the difference of the given algebraic fraction is,

\dfr\dfrac{(x+5)(x+2)}{x(x-3)(x+3)}

<h3>What is the difference? </h3>

Difference is the mathematical operation in which the one number is subtract from another number.

To find the difference of two fraction numbers, we find the least common factor of denominator and write the all numbers as one fraction.

The given expression in the problem is,

\dfrac{2x+5}{x^2-3x}-\dfrac{3x+5}{x^3-9x}-\dfrac{x+1}{x^2-9}

Factorize the denominator of each term as,

\dfrac{2x+5}{x(x-3)}-\dfrac{3x+5}{x(x-3)(x+3)}-\dfrac{x+1}{(x-3)(x+3)}

Here, the least common factor of the denominators is x(x-3)(x+3), therefore, the expression can be written as,

\dfrac{(x+3)(2x+5)-(3x+5)-(x)(x+1)}{x(x-3)(x+3)}\\\dfr\dfrac{2x^2+5x+6x+15-3x-5-x^2-x}{x(x-3)(x+3)}\\\dfr\dfrac{x^2+7x+10}{x(x-3)(x+3)}\\\dfr\dfrac{(x+5)(x+2)}{x(x-3)(x+3)}

Hence, the expression which is equivalent to the difference of the given algebraic fraction is,

\dfr\dfrac{(x+5)(x+2)}{x(x-3)(x+3)}

Learn more about the difference of two fractions here;

brainly.com/question/13222

6 0
2 years ago
Find the diameter of a sphere with the volume 7776pi in^3
svet-max [94.6K]

Answer:

The diameter is 36 inches

Step-by-step explanation:

The volume of a sphere is

\frac{4}{3} \pi {r}^{3}

The given sphere has volume

7776\pi {in}^{3}

We can now equate the formula to the given volume and solve for r.

\frac{4}{3} \pi {r}^{3}  = 7776\pi

{r}^{3}= 7776\pi \times  \frac{3}{4\pi}

{r}^{3}  = 5832

r =  \sqrt[3]{5832}

r = 18

The diameter of the sphere is twice the radius.

Hence

diameter = 2 \times 18 = 36in

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