If the 5 scores have a mean of 8, then their total sum would be 8*5 = 40
Now if one score if added (let's call this score x), there are 6 scores and the mean changes to 9, thus:
(40 + x)/6 = 9
40 + x = 54
x = 14
January . . . $57.85
March . . . . 4 times as much = 4 (57.85) = $231.40
Deposit 78.45 more . . . ($231.40 + 78.45) = <em>$309.85</em> .
Notice that "interest" is never mentioned anywhere in this problem.
In other words, it doesn't matter whether Julie's savings account is
in a bucket in the basement, a mayonnaise jar on the porch, under
her mattress, or in a bank that pays no interest.
Without interest, $309.85 is what she <em><u>does</u></em> have<em><u /></em> in November, which
is about right for savings accounts in banks these days.
What her balance <em><u>should</u></em> be in November is an entirely different subject.
Answer:
2
Step-by-step explanation:
The "average value of function f(x) on interval [a, b] is given by:
f(b) - f(a)
ave. value = ---------------
b - a
Here f(t)=(t-2)^2.
Thus, f(b) = (b - 2)^2. For b = 6, we get:
f(6) = 6^2 - 4(6) + 4, or f(6) = 36 - 24 + 4 = 16
For a = 0, we get:
f(0) = (0 - 2)^2 = 4
Plugging these results into the ave. value function shown above, we get:
16 - 4
ave. value = ------------ = 12/6 = 2
6 - 0
The average value of the function f(t)=(t-2)^2 on [0,6] is 2.
Answer:
<u>Option A) 19 to 25</u>
Step-by-step explanation:
In the last election, 72% of the voters were in favor of a new outlet mall and
28% were against it.
Vanessa creates random samples of the voters using the numbers 1 to 25.
So, There are 25 numbers to represent all the voters
The range of number that could be used to represent the voters who were against the new outlet mall = 28% of 25 numbers = 0.28 * 25 = 7
So, <u>7 numbers only</u> could be used to represent the voters who were against the new outlet mall.
Check the options to find which range has only 7 numbers.
A) 19 to 25 ⇒ 7 numbers
B) 7 to 18 ⇒ 12 numbers
C) 15 to 25 ⇒ 11 numbers
D) 1 to 18 ⇒ 18 numbers
The answer is <u>option A) 19 to 25</u>
