You subtract 5 from both sides to get n=8
It's not possible nothing but 1 times 5 is the only thing that multiplies to 5 and 1+5 doesn't equal 4
Answer:
1)y=-3+5x
2)y=5/2-1/2x
Step-by-step explanation:
for both equations
1) get your y by it self (subtract -5x and your new equation is now -y=-5x+3)
2)(reminder y can't be negative if it is negative) then you divide by -1 of both sides
3) your equation should now be y=5x-3
One way to solve it is writing two equations based on the info so
y = 5x + 10 for members
y = 6x for nonmembers
(the + 10 isn't included in the second equation because nonmembers won't pay a membership fee)
and to find their intersection point (where the values will be the same), you just set them equal to each other:
5x + 10 = 6x
subtract 5x
x = 10 classes
Subtract the second equation from double the first equation:
2x+6y-2x-(-4y)=0
10y=0
Therefore, y=0. Substituting this into the first equation, we see that:
x+3(0)=3
x=3
Therefore, x=3. The solution to this system is x=3, y=0, or (3, 0).
