Answer:
A.0.39 grams
margin of error at 90% confidence intervals is
M.E = 0.39 grams
Step-by-step explanation:
<u>Explanation</u>:-
Given a sample of size n = 25
mean of the sample x⁻ = 15 grams
Standard deviation of the sample 'S' = 1.5 grams
<u>margin of error at 90% confidence intervals is determined by</u>
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The degrees of freedom ν = n-1 = 25-1 =24
The tabulated value t₀.₉₀ = 1.318
Margin of error = 0.3954
<u>Conclusion</u>:-
Margin of error at 90% confidence intervals = 0.3954