Particle Kinetic Theory states that the particles of matter in the 3 states of matter only differ in what?

A 53. 5 mL ample of an 5. 4 % (m / v) KBr olution i diluted with water o that the final volume i 205. 0 mL Expre your anwer to t

gogolik [260]

The concentration after dilution is 1.4%.

We are aware that concentration and volume are related to each other by the formula -

$C_{1}$ $V_{1}$ = $C_{2}$ $V_{2}$ , where we have initial concentration and volume on Left Hand Side and final concentration and volume on Right Hand Side.

Keep the values to calculate final concentration.

$C_{2}$ = (53.5 × 5.4)/205.0

Performing multiplication on Right and Side

$C_{2}$ = 288.9/205.0

Performing division on Right Hand Side

$C_{2}$ = 1.4%

Hence, the final concentration is 1.4%.

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The complete question is -

A 53.5 mL sample of an 5.4 % (m/v) KBr solution is diluted with water so that the final volume is 205.0 mL.

Calculate the final concentration and express your answer to two significant figures and include the appropriate units.

3 0

1 year ago

27. How was the design of the Chernobyl plant different than most modern reactors?

enot [183]

Answer:

I think its C

Im not sure tho hehe

8 0

3 years ago

Assume at exactly 100.0°c and 1.00 atm total pressure, 1.00 mole of liquid water and 1.00 mole of water vapor occupy 18.80 ml an

Grace [21]

Answer 1) : When we calculate the ΔQ = -40.66 kJ (heat of vaporisation).

Then, we can relate the work done with this equation,

ΔW = -PΔV

First we need to calculate the volume, which will be,

Volume of water vapor = (nRT) / (P)

Then, V = (1 mole) X (0.0821 L X atm/mole X K) X (373.15K) / (1atm) = 30.6 liters So, it is given, and verified.

Volume of Water can be used for finding the; Density = M / V

D = ( 1 mole) X (18.02 g/mole) / (18.80 mL) = 0.9585 g/mL

On, substituting the values, we get,

ΔW = -PΔV

Work = - (1 atm) X (0.00188L - 30.62L) X 0.1013kJ/L X atm = 3.10 kJ

hence the work done is 3.10 kJ

Answer 2) Now, for calculating the internal energy, we can use the formula as,

ΔE = ΔQ + ΔW

Here, we have the values of ΔQ = -40.66 kJ and ΔW as = 3.10 kJ

So, we get, ΔE = (-40.66) + (3.10) = - 37.55 kJ

Therefore, the change in the internal energy will be -37.55 kJ.

3 0

3 years ago

A direct relationship can be represented by:

Brut [27]

I believe the correct answer from the choices listed above is option A. A direct relationship can be represented by the expression:

y/x = k

<span>A direct relationship is an expression between two numbers or other variables where an increase or decrease in one variable causes the same change in the other value.</span>

3 0

4 years ago

Read 2 more answers

Calculate the enthalpy of combustion, δh∘comb, for c6h14. you'll first need to determine the balanced chemical equation for the

Vedmedyk [2.9K]

<span>Answer: Enthalpy Change = (6 x -393.5) + (7 x -285.8) - (-204.6) + (19/2) 0.....??? like.. (6 x Enth CO2) + ( 7 x Enth H2O) - (Enth C6H14) + (19/2) Enth O2</span>

3 0

4 years ago