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rjkz [21]
3 years ago
13

Calculate the enthalpy of combustion, δh∘comb, for c6h14. you'll first need to determine the balanced chemical equation for the

combustion of c6h14. express your answer to four significant figures and include the appropriate units.
Chemistry
1 answer:
Vedmedyk [2.9K]3 years ago
3 0
<span>Answer: Enthalpy Change = (6 x -393.5) + (7 x -285.8) - (-204.6) + (19/2) 0.....??? like.. (6 x Enth CO2) + ( 7 x Enth H2O) - (Enth C6H14) + (19/2) Enth O2</span>
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50 mph is a example of
Evgesh-ka [11]
The answer will be speed
3 0
3 years ago
A brick has dimensions of 15 cm x 6.0 cm x 12 cm. What is the volume of the brick in cubi meters?
Likurg_2 [28]
Convert all of the units from centimeters to meters by moving the decimal point over to the left two digits.

0.15 m x 0.06 m x 0.12 m

Volume = length x width x height
             = 0.15 x 0.06 x 0.12 = 0.00108 m^3
6 0
3 years ago
A package of aluminum foil contains 50. ft2 of foil, which weighs approximately 8.5 oz . aluminum has a density of 2.70 g/cm3. w
Serhud [2]
Hello!

We have the following data:

Area (A) = 50 square feet
Mass (m) = 8.5 ounces
Density (d) = 2.70 g/cm³
Volume (V) = ?
Thickness (T) =? (in mm)

To move on, we must transform the area of 50 ft² in cm², let's see:

1 ft² ------- 929,0304 cm²
50 ft² ----- A

A = 50*929,0304

\boxed{A = 46451,52\:cm^2}\Longleftarrow(Area)

In the same way, we will convert the mass of 8.5 oz in grams, see:

1 oz -------- 28,3495 g
8,5 oz ------- m

m = 8,5*28,3495

\boxed{m = 240,97075\:g}\Longleftarrow(mass)

Knowing that the density is 2.70 g/cm³ and the mass is 240.97075 g, we will find the volume, applying the data in the density formula we have:

d =  \dfrac{m}{V} \to V =  \dfrac{m}{d}

V =  \dfrac{240,97075\:\diagup\!\!\!\!\!g}{2,70\:\diagup\!\!\!\!\!g/cm^3}

V = 89,24842593... \to \boxed{V \approx 89,25\:cm^3}

The statement wants to find the thickness of the packaging, for this we have some important data, such as: V (volume) = 89,25 cm³ and Area (A) = 46451,52 cm² and T (thickness) =? (in mm)

In the calculations of Costs in Surface Treatment of a part within the flat geometry, we will use the following formula:

V (volume) = A (Area) * T (Thickness)

89,25\:cm^3 = 46451,52\:cm^2\:*\:T

46451,52\:cm^2*T = 89,25\:cm^3

T =  \dfrac{89,25\:cm^3}{46451,52\:cm^2}

T = 0,001921358009...\:cm

We will convert to millimeters, going through a decimal place on the right

T = 0,01921358009..\:mm

\boxed{\boxed{T \approx 0,0192\:mm\:or\:T\approx \:1,92*10^{-2}\:mm}}\end{array}}\Longleftarrow(thickness)\qquad\checkmark

Hope this helps! :))





8 0
3 years ago
A mixture consists of saw dust, salt, and pebbles. Which of the following instruments or materials would not be useful in separa
andriy [413]

The screen will not be useful in separating the mixture of saw dust, salt and pebbles.

Answer: Option C

<u>Explanation: </u>

The separation of individual elements from the mixture can be done easily if the size of the elements in the mixture is varying significantly. Just like in the present case, the size of sawdust and salt is very small compared to that of pebbles.

So by using sieves having pores of smaller sizes, pebbles can be separated from the mixture as pebbles will not pass through the minute pores. Even depending upon the size of pores, the saw dust can also be separated using it.

Similarly, we can use water also to separate this mixture as sawdust have least density it will float in water surface and pebbles being the highest density will sink and settle in the bottom of the container.

Remaining salt will get dissolved in water which can be obtained by heating the water in order to precipitate the salt. Even filter paper with different mess size will also help in separating this mixture. But as this mixture is not permeable through screen, the screen cannot be used to separate this mixture.

8 0
4 years ago
What is the difference between electronegativity and ionization energy
Katena32 [7]

Answer:

These properties are basically the inverse of each other.

Explanation:

  • Electronegativity is the tendency of an atom to attract an electron and make it a part of its orbital.

        Ionization enthalpy, is the energy required to remove an electron from                        an atom.

  • More electronegative atoms have high ionization enthalpies If the energy required to remove an electron is less, i.e. the atom has more tendency to give electron, it would thus have less tendency to take electron.
  • Values and tendency of electronegativity in the periodic table: In general, the electronegativity of a non‐metal is  larger than that of metal. For the elements of one period the electronegativities increase from  left to right across the periodic table. For the elements of one main group the electronegativities  decrease from top to bottom across the periodic table. To the subgroup elements, there’s no  regular rule.
  • Values and tendency of ionization potential in the periodic table: The first ionization energy is the energy which is  required when a gaseous atom/ion loses an electron to form a gaseous +1 valence ion. The  energy which is required for a gaseous +1 valence ion to loose an electron to form a gaseous +2  valence ion, is called the second ionization energy of an element.  In general, the second ionization energy is higher than the first ionization energy of an element. The first ionization energies of the elements of one period increase from the left to the right  across the periodic table. According to the elements of main group, the first ionization energies  generally decreases from top to bottom across the periodic table.

7 0
4 years ago
Read 2 more answers
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