Ask question

Ask question

All categories

3 years ago

10

Express 512 as a power of 2. a) 28 b) 277 c)299 d) 21010

1 answer:

mote1985 [20]3 years ago

7 0

Answer:

256^2

Step-by-step explanation:

256 power 2 is in a power of 2

You might be interested in

I need help me with number 7

Lina20 [59]

-7=-9+n/8
Add 9 to both sides
2=n/8
Multiply 8 on both sides
Final Answer: 16=n

4 0

4 years ago

More slopeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

tresset_1 [31]

Answer: for me it must be A or C I have a picture how I find my answer.

Step-by-step explanation: Hope this help :D

3 0

3 years ago

Two terms in a geometric sequence are a3=729 and a4=243.

lesantik [10]

<h2>The first term of the given sequence (a) = 6561</h2>

Step-by-step explanation:

Let the first term = a and common difference = d

Given,

$a_{3}$ = 729 and $a_{4}$ = 243

To find, the first term of the given sequence (a) = ?

We know that,

The nth term of a G.P.

$a_{n} =ar^{n-1}$

The 3rd term of a G.P.

$a_{3} =ar^{3-1}$

⇒ $ar^{2}$ = 729 ..............(1)

The 4th term of a G.P.

$a_{4} =ar^{4-1}$

⇒ $ar^{3}$ = 243 ..............(2)

Dividing equation (2) by (1), we get

$\dfrac{ar^{3}}{ar^{2}}$ = $\dfrac{243}{729}$

⇒ $r=\dfrac{1}{3}$

Put $r=\dfrac{1}{3}$ in equation (1), we get

$a(\dfrac{1}{3})^{2}$ = 729

⇒ $a(\dfrac{1}{9})$ = 729

⇒ a = 9 × 729 = 6561

∴ The first term of the given sequence (a) = 6561

8 0

3 years ago

ou are interested in estimating the the mean age of the citizens living in your community. In order to do this, you plan on cons

PolarNik [594]

Answer:

$(\frac{4\sigma}{2.056})^2$ , rounded up, if needed, citizens should be included in the sample, in which $\sigma$ is the standard deviation of the population.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.96}{2} = 0.02$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.02 = 0.98$ , so Z = 2.056.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Within 4 years of the actual mean

We have to find n for which M = 4. So

$M = z\frac{\sigma}{\sqrt{n}}$

$4 = 2.056\frac{\sigma}{\sqrt{n}}$

$2.056\sqrt{n} = 4\sigma$

$\sqrt{n} = \frac{4\sigma}{2.056}$

$(\sqrt{n})^2 = (\frac{4\sigma}{2.056})^2$

$n = (\frac{4\sigma}{2.056})^2$

$(\frac{4\sigma}{2.056})^2$ , rounded up, if needed, citizens should be included in the sample, in which $\sigma$ is the standard deviation of the population.

8 0

3 years ago

Bobby Catches 8 passes in 3 football games. At this rate, how many passes does he catch in 15 games?

alekssr [168]

Answer:

40 passes

Step-by-step explanation:

Take 8/3 which is 2.666666667, then multiply it by 15.

3 0

4 years ago