We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.
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How to get the slope of the line that passes through the points (9, 1) and (10, - 1)?</h3>
A linear equation has the general form:
y = a*x + b
Where a is the slope of the line, and b is the y-intercept.
There is a simple equation to get the slope of a point if we know two points. For a line that passes through ( a, b) and (c, d), the equation for the slope is:
a = (d - b)/(c - a)
In this case we know that our line passes through (9, 1) and (10, -1), then using the above equation, we can see that the slope is:
a = (-1 - 1)/(10 - 9) = -2
We conclude that the slope of the linear equation that passes through the points (9, 1) and (10, -1) is -2.
If you want to learn more about linear equations:
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I believe the answer is the first one because it contains a negative fraction and in the chart some of the numbers are negative
Answer:
31.75 cm is equal to 12.5 in
Step-by-step explanation:
Hi there! Mind trick question again...
The answer is 0.4624159615452.
I hope this is correct! Have a great day!
The asymptote cannot be x= because x can be any number. If you think about it, you can take a number to any exponent.
If x is a positive exponent, y is positive.
If x is a nevative exponent, y decreases, but is still positive. This is because a number to a negative exponent equals 1 over the number to the positive exponent. Thus, it is smaller, but still positive.
If x is 0, y is positive again because anything to the zero is positive 1.
There is no way y could be less than or equal to zero. So, there is an asymptote at y=0.
Also, set the equation equal to 0 and solve. You should end up with 4^x=0. Since no exponenent can make a number zero, this isn't possible, so y cannot equal zero.
Here is the graph for a visual: