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riadik2000 [5.3K]
3 years ago
15

David has been driving for 4 hours at 62.8 km/hr. How many kilometers did he travel in that time?

Mathematics
2 answers:
Murrr4er [49]3 years ago
7 0
I would say 234.221 hshevvwosfueoe
dangina [55]3 years ago
6 0
4 times 62.8 equals 251.2 that's really all you have to do

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48x + 56xy <br><br> .................
Liula [17]

Answer:

The A option is correct since:

48x + 56xy \\ 8x(6 + 7y)

Good luck!

Intelligent Muslim,

From Uzbekistan.

6 0
3 years ago
Simplify:
liubo4ka [24]

Answer:

78.5÷3.14=25

56.272×41.2=2318.4064

429×338×712=103241424

447÷513=0.8713450292

Step-by-step explanation:

hope it will help!

8 0
3 years ago
Quadrilateral ABCD?<br>​
Mashutka [201]

The given quadrilateral is a kite.

Given: Point A (2, 4), B (-2, -5), C (7, -1) and D (7, 4)

Firstly, we find the distance between AD and DC

AD = \sqrt{(7 - 2)^{2} + (4 - 4)^{2}  }

⇒ AD = \sqrt{5^{2} }

⇒ AD = 5

DC = \sqrt{(7 - 7)^{2} + (4 - (-1))^{2} }

⇒ DC = \sqrt{5^{2} }

⇒ DC = 5

Hence, AD = DC = 5

Now, find the distance between AB and BC

AB = \sqrt{(-2 - 2)^{2}  + (-5 - 4)^{2} }

⇒ AB = \sqrt{(-4)^{2} + (-9)^{2}  }

⇒ AB = \sqrt{16 + 81}

⇒ AB = \sqrt{97}

BC = \sqrt{(7 - (-2))^{2} + (-1 - (-5))^{2}  }

⇒ BC = \sqrt{9^{2}  + 4^{2} }

⇒ BC = \sqrt{81 + 16}

⇒ BC = \sqrt{97}

Hence, AB = BC = √97

In the given quadrilateral, the two pair is of equal length and these sides are adjacent to each other.

Hence, it follows the property of kite.

For more questions on quadrilateral, visit:

brainly.com/question/23935806

#SPJ9

6 0
1 year ago
Please help with this and explain how to do it, I'll give 15 points
MrRissso [65]

Answer:

Option (4).

Step-by-step explanation:

Outer diameter of the hollow metallic ball = 10 centimeters

Outer radius of this ball = \frac{10}{2} = 5 cm

Volume of the outer ball V_{1} = \frac{4}{3}\pi (r)^3

                                         = \frac{4}{3}\pi (5)^3

Inner radius of the hollow metallic ball = (5 - 1) = 4 cm

Volume of the inner hollow ball V_{2} = \frac{4}{3}\pi (4)^3

Volume of the metal used in the metallic ball = V_{1}-V_{2}

                                                                           = \frac{4}{3}\pi (5)^3-\frac{4}{3}\pi (4)^{3}

                                                                           = \frac{4}{3}\pi [(5)^3-(4)^3]

Therefore, expression given in option (4) will be used to measure the volume of the hollow metallic ball.

8 0
3 years ago
What is the least common denominator for 2/5 + 3/7
-BARSIC- [3]

Answer:

35

Step-by-step explanation:

6 0
3 years ago
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