Answer:
5(15+4)
Step-by-step explanation:
I think this is the answer. I don't understand the question but I did factor out the problem
The domain of the function are all possible values (x values) which are suitable for the function. The range are all possible y values , when we have already defined the domain.
For the exponential function:The domain of exponential functions<span> is all real numbers. And the range are all real numbers greater than zero.
</span>For the quadratic function: The domain<span> is all real numbers, and the </span>range<span> is all real numbers f(x) such that f(x) ≤ 4.
</span>For the linear function: Domain and range all real numbers.
For the inverse variation function (hyperbola): two asymptotes are excluded from the domain of all real numbers and one excluded from the range.
So, according to these, the exponential function, the quadratic function and the inverse variation function <span>cannot have "all real numbers" as either its domain or its range. Only the linear has.</span>
Answer:

Step-by-step explanation:

2(x+5)=2x+10
(2x+10)(3x-2)=
2x(3x)+10(3x)+2x(-2)+10(-2)
=
=
If your equation is ...

then it has no real solutions, and certainly no integer solutions.
_____
The attached graph show the left side is never equal to the right side of this equation for any real values of t.
Answer:
could be wrong so if AC=12
and B is in-between the B is a half of Ac
which is 6