The probability of randomly chosen tall and obese individuals is 0.30.
Firstly complete the given table and find the total of each row and column.
Tall Medium Short Total
Obese 18 28 14 60
Normal 20 51 28 99
Underweight 12 25 9 46
Total 50 104 51 205
We have to find P(Tall | Obese).
P(Tall | Obese) = P(Tall and Obese) / P(Obese)
Now, P(Tall and Obese) = 18 ÷ 205
And, P(Obese) = 60÷205
Substituting the above values,
P(Tall | Obese) = 18÷205/ 60÷205
P(Tall | Obese) = 18/60
P(Tall | Obese) = 0.30
Hence the probability of a tall and obese individual is 0.30.
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A = 113.47-16.82 = 96.65
B = 119.47-(-16.82) = 136.29
A-B = - 39.64
B-A = 39.64
Hope it helps.
Answer:
x = 2
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y-intercept )
here m = - 
and c = 12
y = - x + 12 ← equation in slope-intercept form
given (x, 5) lies on the line, solve for x by letting y = 5
- x +12 = 5
multiply all terms by 2 to eliminate the fraction
- 7x + 24 = 10 ( subtract 24 from both sides )
- 7x = - 14 ( divide both sides by - 7 )
x = 2
Answer:
Perpendicular and parallel
Answer:
5 weeks
Step-by-step explanation:
Do 40*5 then add the 200 to 25
