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MakcuM [25]
3 years ago
9

What is the mass percentage of oxygen in Ba3(PO4)2? Please help how do I go about figuring this out?

Chemistry
1 answer:
Mice21 [21]3 years ago
6 0

Molecular Mass of Compound.

\\ \sf\longmapsto Ba_3(PO_4)_2

\\ \sf\longmapsto 3(137u)+2(39u+4(16u))

\\ \sf\longmapsto 411u+2(39u+64u)

\\ \sf\longmapsto 411u+2(103u)

\\ \sf\longmapsto 411u+206u

\\ \sf\longmapsto 617u

  • Molecular mass of O in compound=16(4)=64u

\\ \sf\longmapsto Mass\%\:of\:O

\\ \sf\longmapsto \dfrac{64}{617}\times 100

\\ \sf\longmapsto \dfrac{6400}{617}

\\ \sf\longmapsto 10.3\%

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nekit [7.7K]

Answer : The volume of NaOH required to neutralize is, 340 mL

Explanation :

To calculate the volume of base (NaOH), we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.300M\\V_1=85.0mL\\n_2=1\\M_2=0.150M\\V_2=?

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2\times 0.300M\times 85.0mL=1\times 0.150M\times V_2\\\\V_2=340mL

Hence, the volume of NaOH required to neutralize is, 340 mL

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4 years ago
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3 years ago
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Explanation:

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