We have been given that the population of a wildlife habitat is modeled by the equation $p(t)=\frac{360}{1+6.2e^{-0.35t}}$ , where t is given in years. We are asked to find the the number of animals originally transported to the habitat.

To find the the number of animals originally transported to the habitat, we will substitute $t=0$ in our given equation as:

$p(0)=\frac{360}{1+6.2e^{-0.35(0)}}$

$p(0)=\frac{360}{1+6.2e^{0}}$

$p(0)=\frac{360}{1+6.2(1)}$

$p(0)=\frac{360}{7.2}$

$p(0)=50$

Therefore, 50 animals were originally transported to the habitat.

6 0

3 years ago

Jimmy thought he had purchased 7 folders, but purchased 6. What was his percent error?

OleMash [197]

Answer:

Step-by-step explanation:

Percent Error = | Actual Yield-Theoretical/ Theoretical Yield | *100%

Error= |-1/7|*100%= 14.29%

4 0

3 years ago

What is the approximate percent decrease when a fish count goes down from 850 to 500? The percent decrease is approximately 40%.

Korolek [52]

Answer:

<h2><em>The percent decrease is approximately 40%. </em></h2>

Step-by-step explanation:

Step one:

given data

initial count of fish= 850

final count of fish= 500

Required

% decrease

Step two:

% decrease= final-initial/initial*100

substitute

% decrease= 850-500/850*100

% decrease=350/850*100

% decrease= 0.41*100

% decrease= 40.1%

<em>The percent decrease is approximately 40%. </em>

7 0

3 years ago

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