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olya-2409 [2.1K]
3 years ago
13

What’s the answer to this ??

Mathematics
1 answer:
lesya [120]3 years ago
6 0

Answer:

Step-by-step explanation:

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Whats the answer to 45=x(14-x)
ElenaW [278]
45=x(14-x)\\ \\45=14x-x^2\\ \\x^2-14x+45=0\\ \\\Delta = b^{2}-4ac =  (-14)^{2}-4*1* 45=196-180=16 \\ \\x_{1}=\frac{-b-\sqrt{\Delta }}{2a} =\frac{14- \sqrt{16}}{2}=\frac{14-4}{2}= \frac{12}{2}=6\\ \\x_{2}=\frac{-b+\sqrt{\Delta }}{2a} =\frac{14+\sqrt{16}}{2}=\frac{14+4}{2}= \frac{18}{2}=9
3 0
3 years ago
Read 2 more answers
(9·20+60)÷4−16+4·(20·5)
neonofarm [45]

\text {Hello! Let's Solve this Problem!}

\text {The First Step is to Solve the Parentheses:}

\text {90*20=180+60=240}\\\text {20*5=100}

\text {Your new Problem should be: 240/4-16+4+100}

\text {The Next Step is to Divide:}

\text {240/4=60}

\text {Your new Problem should be: 60-16+4*100}

\text {The Next Step is to Subtract:}

\text {60-16=44}

\text {Now the Next Step is to Multiply:}

\text {4*100=400}

\text {The Final Step is to Add:}

\text {44+100=}

\text {Your Answer should be:}

\fbox {444}

\text {Best of Luck!}

\text {-LimitedX}

6 0
3 years ago
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Question 2 <br><br> help pls its hard i forgt how to do it
Arada [10]

Answer: 52

Step-by-step explanation:

a^2+b^2=c^2

x is the hypotenuse (c). You can find the hypotenuse by finding the opposite of the right angle

48^2+20^2=2304+400=2704

√2704=52

x=52

3 0
1 year ago
3x − 15= 3x + 15<br> what is x?
Marina CMI [18]

We are given the following equation and want to find the possible values of x

3x-15=3x+15

Subtract both sides by 3x

3x-15-3x=3x+15-3x

-15=15

Now, we have this weird equation. Since -15 is NOT equal 15 and there is no other way we could have solved for x, there is no real solution to the given equation.

In other words, there is no value of x that makes the equation true.

Let me know if you need any clarifications, thanks!

~ Padoru

7 0
3 years ago
How do you find the area of a circle equation easy? (Also to find points on circle using the equation)
baherus [9]

the area of a circle is A = πr², where r = radius of the circle.

how to find points in the circle? depends on what the scenario is, if you know circle's center and its radius, simply use the distance formula to get any of the points, if you have only the equation of it in standard form, you can use the x,y coordinates with substitution, if you have an sketch, you can get them off the grid, so depends on what you have as components.

8 0
3 years ago
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