AC is a tangent so by definition, it touches the circle at exactly one point (point C) and forms a right angle at the tangency point. So angle ACO is 90 degrees
The remaining angle OAC must be 45 degrees because we need to have all three angles add to 180
45+45+90 = 90+90 = 180
Alternatively you can solve algebraically like so
(angle OAC) + (angle OCA) + (angle COA) = 180
(angle OAC) + (90 degrees) + (45 degrees) = 180
(angle OAC) + 90+45 = 180
(angle OAC) + 135 = 180
(angle OAC) + 135 - 135 = 180 - 135
angle OAC = 45 degrees
Side Note: Triangle OCA is an isosceles right triangle. It is of the template 45-45-90.
Answer:
<em>3y+5x=6</em>
Step-by-step explanation:
<u>Equation of the Line</u>
The equation of a line passing through points (x1,y1) and (x2,y2) can be found as follows:

The line passes through the points (6,-8) and (-3,7), thus:


Simplifying:

Multiplying by 3:


Moving all the variables to the left side:
3y + 5x = 30 - 24
3y + 5x = 6
Answer:
(22,0)
Step-by-step explanation:
1. Select any two points given and find their slope (rise/run)
(-38, 40) and (-23, 30)
slope =
= - 2/3
2. Use the slope and one of the points to create an equation of the line in the format y = mx + b, where m = slope and b = y-intercept.
y = mx + b ⇒ 40 = -2/3 (-38) + b
3. Solve for b
40 = -2/3 (-38) + b
40 = 76/3 + b
40 - 76/3 = b
b = 44/3
4. To find the x-intercept, set y = 0, and solve.
y = -2/3 x + 44/3
0 = -2/3 x + 44/3
2/3 x = 44/3
x = 22
Hope this helped!
<h2>pi divided by four</h2>
Step-by-step explanation:
Let the angle in degrees be 
Let the angle in radians be 
If
is the angle in degrees and
is the angle in radians,

It is given that the 

So,