Divide the polygon into separate shapes. Like a rectangle and then a triangle.
find the areas of those shapes and then add them together.
37 x 10 = 370
21 x 11 = 231
Mark worked 21 Hours, Jack worked 37 Hours.
Answer:
Number of ml of 40% sugar = x = 1000mL
Number of ml of 85% sugar used = y = 800mL
Step-by-step explanation:
Let the
Number of ml of 40% sugar = x
Number of ml of 85% sugar used = y
From the above question, our system of equations is given as:
x + y = 1800mL ....... Equation 1
x = 1800 - y
40% × x + 85% × y = 60% × 1800mL
0.4x + 0.85y = 1080.... Equation 2
We substitute 1800 - y for x in Equation 2
0.4(1800 - y) + 0.85y = 1080
720 - 0.4y + 0.85y = 1080
- 0.4y + 0.85y = 1080 - 720
0.45y = 360
y = 360/0.45
y = 800mL
Solving for x
x = 1800 - y
x = 1800 - 800
x = 1000mL
Therefore,
Number of ml of 40% sugar = x = 1000mL
Number of ml of 85% sugar used = y = 800mL
Full Question:
The 4th term of a g.p. is 40 and the 10th term in the sequence is 2560, what is the 11th term in the sequence ?
Answer:
the 11 the term is 5120
Step-by-step explanation:
Given
Geometry Progression
4th term = 40
10th term = 2560
Required
11 term.
The nth term of a geometric sequence is calculated as follows
Tₙ = arⁿ⁻¹
For the 4th term, n = 4 and Tₙ = 40
Substitute these in the given formula; this gives
40 = ar⁴⁻¹
40 = ar³. --;; equation 1
For the 10th term, n = 10 and Tₙ = 2560
Substitute these in the given formula; this gives
2560 = ar¹⁰⁻¹
2560 = ar⁹. --;; equation 2
Divide equation 2 by 1. This gives
2560/40 = ar⁹/ar³
64 = r⁹/r³
From laws of indices
64 = r⁹⁻³
64 = r⁶
Find 6th root of both sides
(64)^1/6 = r
r = (2⁶)^1/6
r = 2
Substitute r = 2 in equation 1
40 = ar³. Becomes
40 = a * 2³
40 = a * 8
40 = 8a
Divide both sides by 8
40/8 = 8a/8
5 = a
a = 5.
Now, the 11 term can be solved using Tₙ = arⁿ⁻¹ where n = 11
So,
Tₙ = arⁿ⁻¹ becomes
Tₙ = 5 * 2¹¹⁻¹
Tₙ = 5 * 2¹¹⁻¹
Tₙ = 5 * 2¹⁰
Tₙ = 5 * 1024
Tₙ = 5120.
Henxe, the 11 the term is 5120
