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3 years ago

Approximate sqrt (39) to the nearest whole number

Mathematics

1 answer:

Firdavs [7]3 years ago

6 0

Answer:

${ \boxed{ \sqrt{39} \approx 6 }}$

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Free_Kalibri [48]

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2. 0.29069767
3. 0.45977011

7 0

3 years ago

Multiply this expression :: -2/7 • (-3 5/8)

Helen [10]

Answer: 29/28

Step-by-step explanation:

-2/7 x (-3 5/8)

= -2/7 x -29/8

= 2/7 x 29/8 = 1/7 x 29/4

= 29/28

7 0

3 years ago

Which number is less than 4.703

UNO [17]

Answer:

anything less than 4.703 like for example: 4.702,1,3.45

Step-by-step explanation:

pls mark me brainliest

6 0

4 years ago

Read 2 more answers

What is this can you guys help

dangina [55]

Answer:

see below

Step-by-step explanation:

The graph of y=10 is the graph of all the points (x, 10) for any value of x. Each one of those points is 10 units above the x-axis. Together, those points make a horizontal line where y = 10 (!).

3 0

3 years ago

A picture inside a frame is 2 inches longer than it is wide. The picture is in a frame that has a width of 3 inches on each side

geniusboy [140]

Answer:

The dimensions of the frame are 15 in x 13 in

Step-by-step explanation:

Let

x ----> the length of the picture

y ----> the width of the picture

we know that

$x=2+y$ -----> equation A

The area of the picture, including the frame is

$A=(x+6)(y+6)$

$A=195\ in^2$

$195=(x+6)(y+6)$ ----> equation B

substitute equation A in equation B

$195=(2+y+6)(y+6)$

solve for y

$195=(y+8)(y+6)\\y^2+6y+8y+48=195\\\\y^2+14y-147=0$

solve the quadratic equation by graphing

The solution is y=7 in

see the attached figure

<em>Find the value of x</em>

$x=2+7=9\ in$

Find the dimensions of the frame

$x+6=9+6=15\ in$

$y+6=7+6=13\ in$

therefore

The dimensions of the frame are 15 in x 13 in

7 0

3 years ago