615 - 6 = 609
963 - 6 = 957
609=3×3×29
957=3×11×29
HCF=3×29=87
The largest number that divides 615 and 963 leaving remainder 6 in both numbers is 87.
Answer:
Regular = $0.21 per ounce, Family = $0.19 per ounce
Step-by-step explanation:
Regular
16oz = $3.36
Divide by 16 on both sides
1oz = $0.21
Family
40oz = $7.20
divide by 40 both sides
1oz = $0.19
Answer:
(e) The women on the Maryland field hockey team are not a random sample of all female college field
hockey players. Similarly, the women on the Maryland basketball team are not a random sample of all female
college basketball players. However, for the purposes of this question, suppose that these two groups can be
regarded as random samples of all female college field hockey players and all female college basketball
players, respectively. If these were random samples, would you think that female college basketball players
are typically taller than female college field hockey players? Explain your decision using answers to the
previous questions and/or additional reasoning.
Answer:
A = -10.5
Step-by-step explanation:
To find the value of "A", you can plug x = 2 and f(x) = 3 into the equation. This will allow you to simplify and find the value of "A".
f(x) = 4x³ + Ax² + 7x - 1 <---- Original equation
3 = 4(2)³ + A(2)² + 7(2) - 1 <---- Plug x = 2 and f(x) = 3 into equation
3 = 4(8) + A(4) + 14 - 1 <---- Solve 2³ and 2²
3 = 32 + A(4) + 14 - 1 <---- Multiply 4 and 8
3 = 45 + A(4) <---- Combine like terms
-42 = A(4) <---- Subtract 45 from both sides
-10.5 = A <---- Divide by 4
If A = -10.5, the final equation would look like this:
f(x) = 4x³ - 10.5x² + 7x - 1
Answer:
The ratio of the number of bulbs tested to defective bulbs is always 14 to 1.
<u><em>What is the unitary method?</em></u>
The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.
We generally expect industrial processes to produce defects at about the same rate, the proportion of the defective product is generally considered to be a remain constant.
Here, the proportion of defective bulbs is:
1/14 = 2/28 = 6/84
So, it will be 24/336.
The ratio of the number of bulbs tested to defective bulbs is expected to remain constant at about 14.
Please vote for Brainliest and I hope this helps!
