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3 years ago

7-9. A deli sliced 13.7 kilograms of

Mathematics

1 answer:

xxTIMURxx [149]3 years ago

5 0

Answer:

36.23 kilograms of roasted beef

Step-by-step explanation:

If deli sliced 13.7 kilograms (kg) of roasted beef one week

He sliced 22.53 kilograms (kg) the next week

Total sliced kilograms of roasted beef=13.7 kg + 22.53 kg

=36.23 kg

The deli sliced a total of 36.23 kilograms of roasted beef in the two weeks.

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Find the area of the shape below by composing or decomposing.

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If its considered a triangle every unit inside a triangle is 90 square units

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Polygon abc is dilated, rotated and translated to form polygon a’b’c’d. The endpoint of ab at (0,-7) and (8,8), and the endpoint

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3 years ago

What is the difference between the 5th multiple of 7 and 3rd multiple of 2 ?

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Answer:

<h3>5th Multiple of 7 = 35</h3><h3>3rd Multiple of 2 = 6</h3><h2>The Difference</h2>

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3 years ago

Items are inspected for flaws by two quality inspectors. Both inspectors inspect every item and the probability that an item has

Genrish500 [490]

Answer:

a)0.976

b)0.00926

c)0.2402

d)0.35

Step-by-step explanation:

Let $X_i$ be an item passed by inspector i

Let Y be the event that there is a fault in an item

The probability that an item has a flaw is 0.1 i.e. P(Y)=0.1

If a flaw is present ,it will be detected by the first inspector with probability 0.92 i.e. $P(\bar{X_1}|Y)=0.92$

So, $P(X_1|Y)=1-0.92=0.08$

If a flaw is present ,it will be detected by the second inspector with probability 0.7 i.e. $P(\bar{X_2}|Y)=0.7$

So, $P(X_2|Y)=1-0.7=0.3$

If an item does not have a flaw, it will be passed by the first inspector with probability 0.95 i.e. $P(X_1|\bar{Y}) = 0.95$

So, $P(\bar{X_1}|\bar{Y}) = 1-0.95=0.05$

If an item does not have a flaw, it will be passed by the second inspector with probability 0.8 i.e. $P(X_2|\bar{Y}) = 0.8$

So, $P(\bar{X_2}|\bar{Y}) = 1-0.8=0.2$

a)P(found by atleast one inspector | It has flaw )=1-P(found by none inspector | It has flow )

P(found by atleast one inspector | It has flaw )= $1-P(X_1|Y) P(X_2|Y)$

P(found by atleast one inspector | It has flaw )= $1-0.08 \times 0.3$

P(found by atleast one inspector | It has flaw )=0.976

Hence the probability that it will be found by at least one of the two inspectors if it has flaw is 0.976

b) $P(Y|X_1)=\frac{P(X_1|Y) P(Y)}{P(X_1|Y) P(Y)+P(X_1|\bar{Y}) P(\bar{Y})}$

$P(Y|X_1)=\frac{0.08 \times 0.1}{0.08 \times 0.1+0.95 \times 0.9}=0.00926$

C)P( two inspectors draw different conclusions on the same item)= $P(X_1 \cap \bar{X_2} \cap Y)+P(\bar{X_1} \cap X_2 \cap Y)+P(X_1 \cap \bar{X_2} \cap \bar{Y})+P(\bar{X_1} \cap X_2 \cap \bar{Y})$

P( two inspectors draw different conclusions on the same item)=0.2402

$P(Y|(X_1 \cap X_2))=\frac{P(Y \cap X_1 \cap X_2)}{P(X_1 \cap X_2)}\\P(Y|(X_1 \cap X_2))=\frac{P(Y \cap X_1 \cap X_2)}{P(X_1 \cap X_2 \cap Y)+P(X_1 \cap X_2 \cap \bar{Y})}\\P(Y|(X_1 \cap X_2))=0.35$

3 0

3 years ago

Which expression is NOT equivalent to this

Dimas [21]

Answer:

<u>A. 88y -40</u>

Step-by-step explanation:

B is definitely equivalent to 11y-5 because it is reversed so it is the same if it is reversed. and D is equivalent too because 11 divided by 5 equals 2.2 same thing as 22 in this case. and C im not that sure about but i do not think that that is not equivalent...and A. is the answer is NOT equivalent because how the heck do u get 88y-40???????? <u>the answer that is not equivalent is A. 88y-40</u>

<u>Hope this explained well :)</u>

3 0

4 years ago