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2 years ago

Which one is it need help

Mathematics

1 answer:

jeka942 years ago

5 0

<h3>♫ - - - - - - - - - - - - - - - ~Hello There!~ - - - - - - - - - - - - - - - ♫</h3>

➷ To understand this, you need to know one rule:

when indices are separated by parenthesis, they multiply

As per this rule, the correct option would be C

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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ASAP Free points, please solve -2m+36=2(6m-3)?<br>

Komok [63]

Answer:

$m = 3$

Step-by-step explanation:

We can try and isolate m on one side of the equation by following the rules of simplifying equations.

$-2m + 36 = 2(6m - 3)\\\\-2m+36 = 12m - 6\\\\36 = 14m-6\\\\42 = 14m\\\\3 = m$

Hope this helped!

6 0

3 years ago

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How do you solve #18?

LiRa [457]

Pizzas are circles. Area of circles is (pi)r^2.

Then find the cost per in.^2

Smallest cost per in.^2 is better buy.

5 0

3 years ago

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Suppose a simple random sample of size 50 is selected from a population with σ=10σ=10. Find the value of the standard error of t

bogdanovich [222]

Answer:

a) $\sigma_{\bar x} = 1.414$

b) $\sigma_{\bar x} = 1.414$

c) $\sigma_{\bar x} = 1.414$

d) $\sigma _{\bar x} = 1.343$

Step-by-step explanation:

Given that:

The random sample is of size 50 i.e the population standard deviation =10

Size of the sample n = 50

a) The population size is infinite;

The standard error is determined as:

$\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}$

$\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}$

$\sigma_{\bar x} = 1.414$

b) When the population size N= 50000

n/N = 50/50000 = 0.001 < 0.05

Thus ; the finite population of the standard error is not applicable in this scenario;

Therefore;

The standard error is determined as:

$\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}$

$\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}$

$\sigma_{\bar x} = 1.414$

c) When the population size N= 5000

n/N = 50/5000 = 0.01 < 0.05

Thus ; the finite population of the standard error is not applicable in this scenario;

Therefore;

The standard error is determined as:

$\sigma_{\bar x} = \dfrac{\sigma}{\sqrt{n}}$

$\sigma_{\bar x} = \dfrac{10}{\sqrt{50}}$

$\sigma_{\bar x} = 1.414$

d) When the population size N= 500

n/N = 50/500 = 0.1 > 0.05

So; the finite population of the standard error is applicable in this scenario;

Therefore;

The standard error is determined as:

$\sigma _{\bar x} = \sqrt{\dfrac{N-n}{N-1} }\dfrac{\sigma}{\sqrt{n} } }$

$\sigma _{\bar x} = \sqrt{\dfrac{500-50}{500-1} }\dfrac{10}{\sqrt{50} } }$

$\sigma _{\bar x} = 1.343$

7 0

3 years ago

Help please! thanks! <br> Find the length of AB<br> A. 2.89<br> B. 33.13<br> C. 378.63<br> D. 377.19

Naddik [55]

<h3>Answer: 29 miles (approximate)</h3>

======================================================

Explanation:

Segment AB is already given to be 19 miles long.

I'm assuming your teacher meant to ask about side BC, which is side 'a' since it's opposite angle A.

Use the law of cosines to find the missing side

a^2 = b^2 + c^2 - 2*b*c*cos(A)

a^2 = 12^2 + 19^2 - 2*12*19*cos(138)

a^2 = 843.874040417691

a = sqrt(843.874040417691)

a = 29.0495101579647

a = 29 when rounding to the nearest whole number

Side BC is roughly 29 miles long.

8 0

3 years ago

over the course of 4 days the price if stock at ACME corporation fell $28. What was the average change in stock price per day?

Schach [20]

28 divided by 4. So the answer is 7.

5 0

3 years ago

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Which one is it need help​

Which one is it need help