All categories

3 years ago

Can someone help me with number 3 please?

Mathematics

1 answer:

harina [27]3 years ago

3 0

Answer:

-x+y=-2

Step-by-step explanation:

Find the slope and y intercept. Then them into the standard form equation: Ax+By+C

You might be interested in

-2 + (-3) x (-8 + 4)

Ymorist [56]

Answer:

Step-by-step explanation:

-2+(-3)*(-8+4)

-2+(-3)*(-4)

-2+12

4 0

3 years ago

Read 2 more answers

3^4 + 2 ⋅ 5 = ____. (Input only whole numbers.)

meriva

91

Follow the order of operations.

3^4 + 2 * 5

81 + 2 * 5 (Exponent)

81 + 10 (Multiplication)

91 (Addition)

Please consider marking this answer as Brainliest to help me advance.

5 0

3 years ago

Probe that:<br><img src="https://tex.z-dn.net/?f=%20%5Csec%20%5Calpha%20%20%5Csqrt%7B1%20-%20%20%5Csin%28%20%7B%7D%5E%7B2%7D%20%

Nataly [62]

Step-by-step explanation:

<h3> $\sec \alpha \sqrt{1 - \sin ^{2} \alpha } = 1$ </h3>

Prove the LHS

Using trigonometric identities

That's

<h3> $\cos ^{2} \alpha = 1 - \sin^{2} \alpha$ </h3>

<u>Rewrite the expression</u>

We have

<h3> $\sec \alpha \sqrt{ \cos^{2} \alpha }$ </h3>

<h3> $\sqrt{ { \cos }^{2} \alpha } = \cos \alpha$ </h3>

So we have

<h3> $\sec \alpha \times \cos \alpha$ </h3>

Using trigonometric identities

<h3> $\sec \alpha = \frac{1}{ \cos \alpha }$ </h3>

<u>Rewrite the expression</u>

That's

<h3> $\frac{1}{\cos \alpha } \times \cos \alpha$ </h3>

Reduce the expression with cos a

We have the final answer as

As proven

Hope this helps you

7 0

3 years ago

The diagram below shows a sandbox and the frame that surrounds it. What is the area of the frame (the shaded area)? (Giving out

KonstantinChe [14]

Answer:

$2(4x+7)\:ft$

Step-by-step explanation:

$The\:area\:of\:the\:frame: (x+3)(x+5)-(x+1)(x-1)\\=x^{2} +8x+15-x^{2} -1\\=8x+14=2(4x+7)$

4 0

3 years ago

How do I solve 3k2= 27 using common core?

nadezda [96]

<span>Simplifying k3 + 4k2 + 4k = -1k3 + 10k Reorder the terms: 4k + 4k2 + k3 = -1k3 + 10k Reorder the terms: 4k + 4k2 + k3 = 10k + -1k3 </span><span>
</span>

7 0

3 years ago