Original price 23.99 and the markdown 22percent
1 answer:
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ABC is a equilateral triangle .
Proof :-
Let's assume both circles as C1 and C2 [ as shown in the figure ]
- AB is the radius of circle C1
- AB is the radius of Circle C2
AC is the radius of circle C1.
BC is the radius of circle C2 .
AB and AC both are radius of circle C1 so both are equal ie AB = AC .
AB and BC both are radius of circle C 2 so both are equal ie AB = BC .
Hence we conclude that .
AB = BC = AC.
So the triangle is equilateral triangle.
I think this is what you mean. I don't know why the Latex didn't work. Good for you that you can use it.
Reduce the 4/28 to 1/7
Make the 2 minuses into a +
56 is the common denominator.
Answer = [23 + 21 + 8] / 56 = 52 / 56 = 13 / 14 When both numerator and denominator are divided by 4
13 / 14 <<<< answer.
Answer = [23 + 21 + 8] / 56 = 52 / 56 = 13 / 14 When both numerator and denominator are divided by 4
13 / 14 <<<< answer.