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Elena-2011 [213]
2 years ago
10

Use the clustering estimation technique to find the approximate total in the following question. What is the estimated sum of 60

2, 540, 575, and 451? A. 2,200 B. 2,000 C. 1,900 D. 1,800
Mathematics
2 answers:
Airida [17]2 years ago
7 0
ANSWER: A 2,200 (answer when added: 2,168)
zavuch27 [327]2 years ago
7 0

Answer:

A:2200

Step-by-step explanation:

602+540+575+451=2168

Rounded up is 2200 because 68 is closer to 2200 than to 2100.

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An elementary school is offering 2 language classes: one in Spanish (S) and one in French (F). Given that P(S) = 50%, P(F) = 40%
nikklg [1K]

Answer:

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French = 0.5 .

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish = 0.6 .

Step-by-step explanation:

We are given that an elementary school is offering 2 language classes ;

 <em>Spanish Language is denoted by S and French language is denoted by F.</em>

Also we are given, P(S) = 0.5 {Probability of students taking Spanish language}

P(F) = 0.4 {Probability of students taking French language}

P(S\bigcup F) = 0.7 {Probability of students taking Spanish or French Language}

<em>We know that,  </em>P(A\bigcup B)<em>  = </em>P(A) + P(B) -<em> </em>P(A\bigcap B)<em />

So, P(S\bigcap F) = P(S) + P(F) - P(S\bigcup F) = 0.5 + 0.4 - 0.7 = 0.2

P(S\bigcap F) means Probability of students taking  both Spanish and French Language.

Also, P(S)' = 1 - P(S) = 1 - 0.5 = 0.5

         P(F)' = 1 - P(F) = 1 - 0.4 = 0.6

        P(S'\bigcap F') = 1 -  P(S\bigcup F) = 1 - 0.7 = 0.3

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French is given by P(S/F);

  P(S/F) = \frac{P(S\bigcap F)}{P(F)} = \frac{0.2}{0.4} = 0.5

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish is given by P(F'/S');

   P(F'/S') = \frac{P(S'\bigcap F')}{P(S')} = \frac{1- P(S\bigcup F)}{1-P(S)} = \frac{0.3}{0.5} = 0.6 .

Note: 2. A pair of fair dice is rolled until a sum of either 5 or 7 appears  ; This question is incomplete please provide with complete detail.

7 0
3 years ago
What is the GCF of 36 and 84
FinnZ [79.3K]
The greatest common factor( GCF) of 36 and 84 is 12.
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3 years ago
Simplify. (x6 y3)(−8xy2)(−6x3)
meriva
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We first would <u></u><u>(first)</u> simplify the following:

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3 years ago
Solve for w.<br> 4 = 0.25(w-4.3)
Snezhnost [94]

W=20.3

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8 0
3 years ago
A set of magical wand prices are normally distributed with a mean of 50 dollars and a standard deviation of 4 dollars. A blackth
Anna11 [10]

Complete Question

A set of magical wand prices are normally distributed with a mean of 50 dollars and a standard deviation of 4 dollars. A blackthorn wand has a price of 45.20. What proportion of wand prices are lower than the price of the blackthorn wand? You may round your answer to four decimal places

Answer:

0.1151

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score = $45.20

μ is the population mean = $50

σ is the population standard deviation = $4

We are solving for x < 45.20

Hence:

z = 45.20 - 50/4

z = -1.2

Probability value from Z-Table:

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