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finlep [7]
3 years ago
9

I’m completely lost can someone help me

Mathematics
2 answers:
jeyben [28]3 years ago
8 0

i think the answer its 40 ?

djverab [1.8K]3 years ago
4 0

I am assuming they are letting you use a calculator. To find the angle of G, you need to use the sin function first and then use the inverse of the sin which is sin^-1

sin = opposite / hypotenuse

sin = 15 / 17

Now insert 15/17 into the function sin()^-1

sin(15/17)^-1 = 61.92 = G = 62 degrees

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Write an absolute value inequality for each of the following. Then graph the
n200080 [17]

An absolute value inequality for "all numbers less than 7 and greater than -7" is given by |x| < 7.

<h3>How to write an absolute value inequality?</h3>

Based on the information provided, we can logically deduce that the statement describes an intersection of set because the word "and" was used.

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1 year ago
Here is a triangular pyramid and its net.
bazaltina [42]

Answer:

a) Area of the base of the pyramid = 15.6\ mm^{2}

b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

Step-by-step explanation:

We are given the following dimensions of the triangular pyramid:

Side of triangular base = 6mm

Height of triangular base = 5.2mm

Base of lateral face (triangular) = 6mm

Height of lateral face (triangular) = 8mm

a) To find Area of base of pyramid:

We know that it is a triangular pyramid and the base is a equilateral triangle. \text{Area of triangle = } \dfrac{1}{2} \times \text{Base} \times \text{Height} ..... (1)\\

{\Rightarrow \text{Area of pyramid's base = }\dfrac{1}{2} \times 6 \times 5.2\\\Rightarrow 15.6\ mm^{2}

b) To find area of one lateral surface:

Base = 6mm

Height = 8mm

Using equation (1) to find the area:

\Rightarrow \dfrac{1}{2} \times 8 \times 6\\\Rightarrow 24\ mm^{2}

c) To find the lateral surface area:

We know that there are 3 lateral surfaces with equal height and equal base.

Hence, their areas will also be same. So,

\text{Lateral Surface Area = }3 \times \text{ Area of one lateral surface}\\\Rightarrow 3 \times 24 = 72 mm^{2}

d) To find total surface area:

Total Surface area of the given triangular pyramid will be equal to <em>Lateral Surface Area + Area of base</em>

\Rightarrow 72 + 15.6 \\\Rightarrow 87.6\  mm^{2}

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b) Area of one lateral face = 24\ mm^{2}

c) Lateral Surface Area = 72\ mm^{2}

d) Total Surface Area = 87.6\ mm^{2}

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