<u><em>Answer:</em></u>
Open
<u><em>Explanation:</em></u>
An open equation is an equation that has variables and CAN be solved
<u>Example</u>: 2x = 4 ......> can be solved giving ......> x = 2
A false equation is one where both sides can NEVER be equal
<u>Example:</u> 15 = 2(3) + 1 ..........> 15 can never be equal to 7
A true equation is one having no variables and both sides are ALWAYS equal
<u>Example:</u> 2(3) + 1 = 2(2) + 3 ........> 7 will always be equal to 7
Now, the given equation is:
4y + 8 = 6y + 3
Let's try to solve is:
4y + 8 = 6y + 3
6y - 4y = 8 - 3
2y = 5
y = 2.5
Therefore, the given equation contains a variable and can be solved which means that it is an open equation
Hope this helps :)
9x-20=7
9x=27
x=3
Hope that helps you :)
Substitute
, so that

Then the resulting ODE in
is separable, with

On the left, we can split into partial fractions:

Integrating both sides gives




Now solve for
:


Answer:
Multiples of 120 are 120, 240, 360, 480, 600, 720, 840 etc; Multiples of 150 are 150, 300, 450, 600, 750, 900 etc; Therefore, the least common multiple of 120 and 150 is 600.
Least common multiple (LCM) of 19600 and 19619 is 384532400.
Answer: 276 grams.
Step-by-step explanation: