What is cos A for this triangle?
1 answer:
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To solve, you must make one side of the equation equal to zero. We can do this by subtracting 3x on both sides of the equation.
<span>x^2 + 7x = 3x
</span> - 3x -3x
x^2 + 4x = 0.
Then we substitute the equation into the quadratic equation.
Where a = 1 b = 4 and c = 0
We first solve whats inside the square root.
Now we solve for -4 and 4.
Then divide both answer by 2
The division of any by zero is zero
So the answer are x = -4 and x = 0
<span>x^2 + 7x = 3x
</span> - 3x -3x
x^2 + 4x = 0.
Then we substitute the equation into the quadratic equation.
Where a = 1 b = 4 and c = 0
We first solve whats inside the square root.
Now we solve for -4 and 4.
Then divide both answer by 2
The division of any by zero is zero
So the answer are x = -4 and x = 0
Option C: (x+4) and (x-1) are the factors of the equation
Explanation:
Given that the equation is
We need to determine the factors of the equation.
Splitting the middle term, we get,
Grouping the terms, we have,
Let us factor out the term (x+4), we have,
Thus, the factors of the equation are (x+4) and (x-1)
Hence, Option C is the correct answer.