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valentina_108 [34]
3 years ago
7

What is cos A for this triangle?

Mathematics
1 answer:
mojhsa [17]3 years ago
5 0

Answer:

48/ 73

Step-by-step explanation:

With reference angle A

perpendicular (p) = 55

base (b) = 48

hypotenuse (h) = 73

Now

Cos A

= b/h

= 48/73

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One litre of milk is poured into a cylindrical container of radius 10 cm. Calculate the depth of the milk in cm)to 2 dp. ( take
wel

Answer:

Depth=3.18cm

Step-by-step explanation:

V=πr2h

1LITRE=1000CM3

v=1000cm³

1000cm3=3.142×10²×Depth

Depth= 1000/3.142×100

Depth=3.18cm

8 0
3 years ago
In a certain college, 33% of the physics majors belong to ethnic minorities. Of 8 students are selected at random from the physi
tiny-mole [99]

Answer: 0.0187

Step-by-step explanation:

The binomial distribution formula for probability :-

P(x)=^nC_xp^x(1-p)^{n-x}, where P(x) is the probability of getting success in x trials , n is the total number of trials and p is the probability of getting success in each trial.

Given : The probability that the physics majors belong to ethnic minorities =0.33

Number of students selected : n= 8

Now, the probability that more than 5 belong to an ethnic minority :-

P(x>5)=P(6)+P(7)+P(8)\\\\=^8C_6(0.33)^6(0.67)^{2}+^8C_7(0.33)^7(0.67)^{1}+^8C_8(0.33)^8(0.67)^{0}\\\\=(\dfrac{8!}{6!2!})(0.33)^6(0.67)^{2}+(8)(0.33)^7(0.67)^{1}+(0.33)^8(0.67)^{0}\\\\=0.0186577086013\approx0.0187

Hence, the probability that more than 5 belong to an ethnic minority = 0.0187

7 0
3 years ago
If < A and < B form a linear pair, and < A = x - 13 degrees, and < B = x + 7 degrees, then find x. Select one: a. 12
Andreas93 [3]

The correct value of "x" will be "93".

According to the question,

  • A linear pair of sum to 180°,

then

→ x-13+x+7=180

→             2x -6=180

By adding "6" both sides of the equation, we get

→       2x-6+6=180-6

→                   2x=186

→                     x = \frac{186}{2}

→                     x = 93

Thus "option d" is the right answer.  

Learn more:

brainly.com/question/19152299

8 0
3 years ago
Later, someone wants to use the data to find the amount of water at times before the sensor started. What should the sensor have
valkas [14]

it 4.56 that how i know because

6 0
3 years ago
An article describes a study comparing two methods of measuring mean arterial blood pressure. The auscultatory method is based o
zzz [600]

Answer:

p_v =P(t_{(5)}>0.499) =0.319

The p value is higher than any significance level given for example \alpha=0.05,0.1, so then we can conclude that we FAIL to reject the null hypothesis. So we don't have enough evidence to conclude that the mean reading is greater for the auscultatory method at 5% or 10% of significance.

Step-by-step explanation:

A paired t-test is used to compare two population means where you have two samples in  which observations in one sample can be paired with observations in the other sample. For example  if we have Before-and-after observations we can use it.  

Let put some notation  

x=Auscultatory method , y = Oscillatory method

x: 74 86 84 79 70 78 79 70

y: 70 85 90 110 71 80 69 74

The system of hypothesis for this case are:

Null hypothesis: \mu_x- \mu_y \leq 0

Alternative hypothesis: \mu_x -\mu_y >0

The first step is define the difference d_i=x_i-y_i, that is given so we have:

d: 6.6, 4.2, -5.5, -3.1, 9.3, -3.9

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}=1.267

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\sqrt{\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1}} =6.215

The fourth step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{1.267 -0}{\frac{6.215}{\sqrt{6}}}=0.499

The next step is calculate the degrees of freedom given by:

df=n-1=6-1=5

Now we can calculate the p value, since we have a right tailed test the p value is given by:

p_v =P(t_{(5)}>0.499) =0.319

The p value is higher than any significance level given for example \alpha=0.05,0.1, so then we can conclude that we FAIL to reject the null hypothesis. So we don't have enough evidence to conclude that the mean reading is greater for the auscultatory method at 5% or 10% of significance.

5 0
3 years ago
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