The self-inductance of the solenoid is 8.25 mH.
The given parameters;
- <em>number of turns, N = 1700 turn</em>
- <em>length of the solenoid, l = 55 cm = 0.55 m</em>
- <em>diameter of solenoid, d = 4 cm</em>
- <em>radius of the solenoid, r = 2 cm = 0.02 m</em>
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The area of the solenoid is calculated as follows;
The self-inductance of the solenoid is calculated as follows;
Thus, the self-inductance of the solenoid is 8.25 mH.
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Answer:
A) L = 0.496 m, B) the movement of the elevator upwards decreases the angular velocity of the pendulum
Explanation:
A) The motion of a simple pendulum is a harmonic motion with angular velocity
w² = g /L
angular velocity and frequency are related
w = 2π f
we substitute
4π² f² = g /L
L =
let's calculate
L = 9.8 / 4 pi² 0.5
L = 0.496 m
B) To see the effect of the elevator acceleration (aₐ), let's use Newton's second law.
At the acceleration from the vertical direction upwards, let's decompose it is a component parallel to the movement and another perpendicular
sin θ = a_parallel / aₐ
a_parallel = aₐ sin θ
this component of the acceleration is in the opposite direction to the movement of the system, so it must be negative
- W sin θ = m (a - a_parallel)
- mg sin θ = m ()
all angles are measured in radians, therefore the angular displacement is
s = L θ
We solve the system for small angles
sin θ = θ
we substitute
- mg θ + m aₐ θ = m L
this is the same equation of the simple pendulum therefore the angular velocity is
w² =
When analyzing this expression, we see that the movement of the elevator upwards decreases the angular velocity of the pendulum
How a nuclear reactor works is that a nuclear reaction goes on in basically a very big tank of water, it acts like a kettle it heats up water which turns into steam to power a turbine so the actual component would either be the turbine or the steam.